Answer:
468
Step-by-step explanation:
Formula for infinite sum of geometric series is;
S_∞ = a1/(1 - r)
Where;
a1 is first term
r is common ratio
We are given;
a1 = 156
r = ⅔
Thus;
S_∞ = 156/(1 - ⅔)
S_∞ = 156/(⅓)
S_∞ = 468
This is a typical radioactive decay problem which uses the general form:
A = A0e^(-kt)
So, in the given equation, A0 = 192 and k = 0.015. We are to find the amount of substance left after t = 55 years. That would be represented by A. The solution is as follows:
A = 192e^(-0.015*55)
<em>A = 84 mg</em>
Tan(θ) = 3 tan(θ), 0° ≤ θ ≤ 360°
Solve for θ to the nearest degree.
tan(θ) = 3 tan(θ)
Subtract tan(θ) from both sides:
0 = 2 tan(θ)
Divide by 2 both sides:
tan(θ) = 0
If (x,y) is a point on the terminal ray of θ,
then tan(θ) = y/x = 0, and y = 0.
y = 0 ==> θ = 0°, 180°, or 360° in the interval 0° ≤ θ ≤ 360°.
First, we will convert the fraction and percentage to decimal
Then arrange from least to greatest
Bears 57% = 0.57
Tigers 5/8 =0.625
Mustangs = 0.65
Re-arranging from least to greatest
0.57, 0.625, 0.65
Bears, Tigers, Mustangs
