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Yanka [14]
2 years ago
14

What has she done wrong?

Mathematics
1 answer:
Strike441 [17]2 years ago
8 0

Answer:

see explanation

Step-by-step explanation:

Her error is in squaring (2y)²

She has (2y)² = 2y²

when it should be 2y × 2y = 4y²

Then

(2y)² = 6² + 8²

4y² = 36 + 64

4y² = 100 ( divide both sides by 4 )

y² = 25 ( take square root of both sides )

y = \sqrt{25} = 5

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PLEASE HELP
Savatey [412]
Correct Answer: Option A

The next step in simplification will be to convert the squared term so that it no longer contains a square.

So, we are to simplify the term cos^{2}(2x)

Using the half-angle identity we can write:

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Using this value, the equation becomes:

sin^{4}x=1-2cos(2x)+ \frac{ \frac{1+cos(4x)}{2} }{4}

Therefore, option A is the correct answer.
4 0
3 years ago
BRAINLY FOR THE FASTEST WITH GOOD EXPLANATIONS
Neporo4naja [7]

So, when we're tasked with things like this, rewriting everything in terms of sine and cosine and combining fractions often trivializes things, so doing just that gives us:

\frac{\frac{1}{\cos{x}}-\frac{1}{\sin{x}}}{\frac{\cos{x}}{\sin{x}}-1}= \\\frac{\frac{=(\cos{x}-\sin{x})}{\cos{x}\sin{x}}}{\frac{\cos{x}}{\sin{x}}-\frac{\sin{x}}{\sin{x}}}=\\\frac{-(\cos{x}-\sin{x})}{\cos{x}\sin{x}}*\frac{\sin{x}}{\cos{x}-\sin{x}}=\\-\frac{1}{\cos{x}}

So out expression is 1/cos(x).

4 0
2 years ago
What is the slope of a line that is parallel to the line y=3/4x+2
MariettaO [177]
The slope is m=3/4. Hope this helped you with your work let me know if I got the answer correct.
3 0
3 years ago
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Which of the following functions has the same horizontal asymptote as the function graphed below?
Alla [95]

Answer:

In most cases, there are two types of functions that have horizontal asymptotes. Functions in quotient form whose denominators are bigger than numerators when x is large positive or large negative.

Step-by-step explanation:

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