Three times the larger of two numbers is equal to four times the smaller. The sum of the numbers is 21. Find the numbers.
1 answer:
X= smaller number
y= larger number
We will have two equations to work with so we can solve for the variables.
EQUATION 1:
3 * y= 4 * x
3y= 4x
subtract both sides by 3y
0= 4x - 3y
EQUATION 2:
21= x + y
SOLVE:
solve for one variable in equation 2
21= x + y
subtract both sides by y
21-y= x
Substitute x= 21-y in equation 1:
0= 4x - 3y
0= 4(21-y) - 3y
0= (4*21) + (4*-y) - 3y
0= 84 - 4y - 3y
0= 84 - 7y
add 7y to both sides
7y= 84
divide both sides by 7
y= 12
Substitute y=12 in either equation to solve for x:
21= x + y
21= x + 12
subtract both sides by 12
9= x
CHECK:
0= 4x - 3y
0= 4(9) - 3(12)
0= 36 - 36
0= 0
ANSWER: x=9 and y=12
Hope this helps! :)
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Given:
AC = √(-2-3)² + (6-2)²
AC = √ -5² + 4²
AC = √ 25 + 16
AC = √41
AC = 6.40
I am assuming that the triangle is an equilateral triangle. This means that all sides are equal.
AC = AB = BC
Perimeter = 6.40 * 3 sides = 19.20
Each number contains a different amount than others.
C should be the answer
Hope this helps
Answer:
if this isn't what you're asking then im sorry but 4870?
Answer:
-2 ± √19
Explanation:
Quadratic formula
Hope this helps!
