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lana66690 [7]
3 years ago
11

Which steps could be used to solve this story problem? Jennifer made some dough for pastry treats. She used 5 times as much flou

r as oil to make the dough. Jennifer used 2 cups of oil. She used 4 more cups of water than oil. How many cups of these ingredients did Jennifer use altogether? Choose ALL answers that are correct. A. Multiply 5 × 4. Divide that quotient by 2. Add that sum to 2. B. Add 2 + 2 + 2 + 2 + 2. Add 4 + 2. Add the sums. Add that sum to 2. C. Multiply 5 × 2. Add 4 + 2. Add the product and the sum. Add that sum to 2. D. Add 2 + 2 + 2 + 2. Subtract 5 – 2. Add the sum and difference. Add that sum to 2.
Mathematics
1 answer:
RideAnS [48]3 years ago
8 0
C should be the answer
Hope this helps
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A slice is made parallel to the base of a right rectangular pyramid.
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Look like whatever <span>3.5×2</span> is. (7)
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1. 4x-8+2x+-5x+x²-3=<br> 2.3x+5x=<br> 3.2r+4+3x-2=<br> 4.3x-2y-x+5y=<br> 5.2y²-8y³+5y-5y²+4y³=
Marrrta [24]
1. 4x - 8 + 2x + (-5x) + x^2 - 3 = 4x - 8 + 2x - 5x + x^2 - 3...now, we just combine like terms....lets group them...it will be easier ...x^2 + (4x + 2x - 5x ) - 8 - 3 = x^2 + x - 11

2. 2x + 5x = 8x

3. 2r + 4 + 3x - 2 = 3x + 2r + (4 - 2) = 3x + 2r + 2

4. 3x - 2y - x + 5y = (3x - x) + (5y - 2y) = 2x + 3y

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    -4y^3 - 3y^2 + 5y
3 0
3 years ago
Jason deposited $18 000 in a bank that offers an interest rate of 5% per annum compounded
8_murik_8 [283]

Answer:

$1995.97.

Step-by-step explanation:

Amount in bank after 20 days =

18000(1 + 0.05/365)^20

= $18049.38

So H = 18049.38 - 16093.41

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3 0
2 years ago
What is 15% of 60 show your work to prove your answer
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3 0
3 years ago
Read 2 more answers
In a home theater system, the probability that the video components need repair within 1 year is 0.02, the probability that the
earnstyle [38]

Answer:

(a) The probability that at least one of these components will need repair within 1 year is 0.0278.

(b) The probability that exactly one of these component will need repair within 1 year is 0.0277.

Step-by-step explanation:

Denote the events as follows:

<em>A</em> = video components need repair within 1 year

<em>B</em> = electronic components need repair within 1 year

<em>C</em> = audio components need repair within 1 year

The information provided is:

P (A) = 0.02

P (B) = 0.007

P (C) = 0.001

The events <em>A</em>, <em>B</em> and <em>C</em> are independent.

(a)

Compute the probability that at least one of these components will need repair within 1 year as follows:

P (At least 1 component needs repair)

= 1 - P (No component needs repair)

=1-P(A^{c}\cap B^{c}\cap C^{c})\\=1-[P(A^{c})\times P(B^{c})\times P(C^{c})]\\=1-[(1-0.02)\times (1-0.007)\times (1-0.001)]\\=1-0.97216686\\=0.02783314\\\approx 0.0278

Thus, the probability that at least one of these components will need repair within 1 year is 0.0278.

(b)

Compute the probability that exactly one of these component will need repair within 1 year as follows:

P (Exactly 1 component needs repair)

= P (A or B or C)

=P(A\cap B^{c}\cap C^{c})+P(A^{c}\cap B\cap C^{c})+P(A^{c}\cap B^{c}\cap C)\\=[0.02\times (1-0.007)\times (1-0.001)]+[(1-0.02)\times 0.007\times (1-0.001)]\\+[(1-0.02)\times (1-0.007)\times 0.001]\\=0.02766642\\\approx 0.0277

Thus, the probability that exactly one of these component will need repair within 1 year is 0.0277.

7 0
3 years ago
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