Answer:
Can you reupload your graph, I don't think you attached it to your question.
The e vertex of the decagon will be in the top position after rotating it counterclockwise by 3 times the smallest angle of rotation.
Which vertex will be in the top position of the regular decagon?
A regular decagon has 10 sides of equal lengths with points labeled 'a' through 'j' clockwise. It is given that the point a is the top-left point. Hence, the the vertex which is in the the top position currently is 'b'.
Now, the smallest angle of rotation will be the angle between the two sides of the decagon.
In the first rotation by the smallest angle in counterclockwise direction, point 'c' will come to the top position. In the second rotation by the smallest angle in counterclockwise direction, point 'd' point will become the top most vertex. Finally, after the third similar rotation, 'e' vertex will be in the top position of the decagon. (Refer the attached diagram)
Learn more about decagon here:
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Answer:
Wait no I apologize. This is the right one.
Key features include: intercepts; intervals where the function is increasing, decreasing, positive, or negative; relative maximums and minimums; symmetries; end behavior; and periodicity.
Answer:
- quotient: 10x +16
- remainder: 28x^2 +10x +22
Step-by-step explanation:
The attachment shows the steps.
quotient: 10x +16
remainder: 28x^2 +10x +22
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Polynomial long division is easier than numerical long division because you only need to examine the first terms to determine the quotient term.
The first quotient term is 10x^4/x^3 = 10x.
The second quotient term is 16x^3/x^3 = 16.
When the leading dividend term is lower degree than the divisor, that dividend is the remainder.
Answer:
the two similar are the two side ones