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2 years ago

Whats the answer????

Mathematics

1 answer:

Citrus2011 [14]2 years ago

5 0

Step-by-step explanation:

the general slope intercept form is

y = ax + b

a is the slope (and always the factor of x). it is expressed as ratio y/x indicating how many units y changes, when x changes a certain amount of units when going from one point to another.

b is the y-intercept, the y value of the point, where the line crosses the y-axis (in other words : the y value when x = 0).

so, look at the chart. where do we see points with integer coordinates (these are the easiest to read correctly and work with) ?

I see for example (0, -6) and (4, -7).

to go from the first to the second point :

x changes by +4 units (from 0 to 4).

y changes by -1 unit (from -6 to -7).

the slope a is therefore -1/4.

and the first point i picked gives us also automatically the y-intercept (-6).

so, the line equation is

y = (-1/4)x - 6

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Rewrite ^3 sqrt 27x-81-5 to make it easy to graph a translation. Describe the graph.

iragen [17]

First we have to rewrite this function.Instead of :^3 sqrt (...) we can write : (...)^(1/3).
f ( x ) = ( 27 x - 81 ) ^(1/3) - 5 = ( 27 * ( x - 3 ) ) ^(1/3) - 5 = = 3 * ( x - 3 )^(1/3) - 5 And this makes it easy to graph a translation.The parent function is y = x^(1/3). The zero of this function is ( 0, 0 ).
Then it will be stretched vertically by a factor of 2 and translated: 3 units right and 5 units down.

8 0

3 years ago

Use spherical coordinates. Find the volume of the solid that lies within the sphere x^2 + y^2 + z^2 = 81, above the xy-plane, an

Natasha_Volkova [10]

Answer:

The volume of the solid is 243 $\sqrt{2} \ \pi$

Step-by-step explanation:

From the information given:

BY applying sphere coordinates:

0 ≤ x² + y² + z² ≤ 81

0 ≤ ρ² ≤ 81

0 ≤ ρ ≤ 9

The intersection that takes place in the sphere and the cone is:

$x^2 +y^2 ( \sqrt{x^2 +y^2 })^2 = 81$

$2(x^2 + y^2) =81$

$x^2 +y^2 = \dfrac{81}{2}$

Thus; the region bounded is: 0 ≤ θ ≤ 2π

This implies that:

$z = \sqrt{x^2+y^2}$

ρcosФ = ρsinФ

tanФ = 1

Ф = π/4

Similarly; in the X-Y plane;

z = 0

ρcosФ = 0

cosФ = 0

Ф = π/2

So here; $\dfrac{\pi}{4} \leq \phi \le \dfrac{\pi}{2}$

Thus, volume: $V = \iiint_E \ d V = \int \limits^{\pi/2}_{\pi/4} \int \limits ^{2\pi}_{0} \int \limits^9_0 \rho ^2 \ sin \phi \ d\rho \ d \theta \ d \phi$