<h3>
Answer:</h3>
See attached graphs.
<h3>
Step-by-step explanation:</h3>
You are being asked to observe the graphs of the various equations and identify something they have in common. To answer the question, it usually works well to do exactly what the question asks you to do.
a: All three lines have a slope of at least 1 and pass through the origin.
b: These lines all have the same slope. They are parallel.
c: All three lines have a slope less than 1 and pass through the origin.
d: These are all the same line.
e: All of these lines intersect at the point (2, -2).
_____
<em>Comment on the graphs</em>
The number of attachments allowed here is limited, so some graphs have been combined. Where there are 3 lines, the first is red, the second is blue, the third is green.
Graphs for (a) and (c) appear on the same page. The graphs for (c) are shown as dashed lines.
Graphs for (b) and (d) appear on the same page. The graph for (d) is shown in orange (as a dashed line). All threee lines look exactly like this.
_____
<em>Comment on the graphing program</em>
These are graphed using the Desmos on-line graphing calculator. It has a tutorial available and is not difficult to learn for most simple graphing applications. (It prefers the variables x and y.) Graphs can be saved for later. (Here, screen shots are used because Brainly doesn't like external links.)
If you subtract the two you will get 5.5
Answer:
4.92% probability that the third strike comes on the seventh well drilled
Step-by-step explanation:
For each drill, there are only two possible outcomes. Either it is a strike, or it is not. Each drill is independent of other drills. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

In which
is the number of different combinations of x objects from a set of n elements, given by the following formula.

And p is the probability of X happening.
20% chance of striking oil.
This means that 
What is that probability that the third strike comes on the seventh well drilled
2 stikers during the first 6 drills(P(X = 2) when n = 6)[/tex]
Strike during the 7th drill, with 0.2 probability. So

In which


Then

4.92% probability that the third strike comes on the seventh well drilled
If you are saying it is fractions a 4/5 to 3/5 then it is decreasing
but if you are saying it is fractions like 4/3 to 5/5 then it is well it is still decreasing
Answer:

Step-by-step explanation:
The rotation by angle
formulas are

To eliminate the xy-term, we have to rotate by 45°, so


Substitute them into the equation 
