Sum of Interior Angles of any poligon, where n is the number of sides: =
(n-2) × 180°
---------------------
(7 - 2) * 180° =
5 * 180 =
900°
[d]
1a:
580 - (580 × .1) - 20
580 - (58) - 20
522 - 20
502
1b:
990 - (990 × .25) - 20
990 - (247.5) - 20
742.5 - 20
722.5
I'm not sure how to solve #2.
Answer:
The answer is in the media.Good luck!
Answer:
Step-by-step explanation:
7
The graphs arey=(1/3)x^2
and y=3
they intersect at x=3
so the limits are x=0 and 3
to rotate it about y=k, minus k from every function

which evaluates to 72/5pi
A is asnwer