Answer:
225
Step-by-step explanation:
The sum of this series is given by the formula:
![S_n=\frac{n}{2}[2a+(n-1)d]](https://tex.z-dn.net/?f=S_n%3D%5Cfrac%7Bn%7D%7B2%7D%5B2a%2B%28n-1%29d%5D)
Where
S_n is the sum
a is the first term (we get this by plugging in n = 1 into "2n-1", we have 2(1) - 1 = 1)
n is the number of terms (the sum is defined for n = 1 to n = 15, so 15 terms)
d is the common different (the difference is successive terms. Here, 2nd term would be 2(2) - 1 = 3, and first term was 1, so d = 3 -1 = 2)
<em>plugging in the info, we will get the sum:</em>
<em>
</em>
<em>The sum is 225</em>
2x+5=x-8
-x on both sides
x+5=8
-5 on both sides
x=-13
Answer:

General Formulas and Concepts:
<u>Algebra I</u>
<u>Calculus</u>
Antiderivatives - integrals/Integration
Integration Constant C
U-Substitution
Integration Property [Multiplied Constant]: 
Trig Integration:
Step-by-step explanation:
<u>Step 1: Define</u>
<u />
<u />
<u />
<u>Step 2: Integrate Pt. 1</u>
- [Integral] Factor fraction denominator:

- [Integral] Integration Property - Multiplied Constant:

<u>Step 3: Identify Variables</u>
<em>Set up u-substitution for the arctan trig integration.</em>

<u>Step 4: Integrate Pt. 2</u>
- [Integral] Substitute u-du:

- [Integral] Trig Integration:
![\displaystyle \frac{1}{9}[\frac{1}{\frac{2}{3}}arctan(\frac{u}{\frac{2}{3}})] + C](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7B1%7D%7B9%7D%5B%5Cfrac%7B1%7D%7B%5Cfrac%7B2%7D%7B3%7D%7Darctan%28%5Cfrac%7Bu%7D%7B%5Cfrac%7B2%7D%7B3%7D%7D%29%5D%20%2B%20C)
- [Integral] Simplify:
![\displaystyle \frac{1}{9}[\frac{3}{2}arctan(\frac{3u}{2})] + C](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7B1%7D%7B9%7D%5B%5Cfrac%7B3%7D%7B2%7Darctan%28%5Cfrac%7B3u%7D%7B2%7D%29%5D%20%2B%20C)
- [integral] Multiply:

- [Integral] Back-Substitute:

Topic: AP Calculus AB
Unit: Integrals - Arctrig
Book: College Calculus 10e
Wait when x= 2 or -4? is the second part options or 5(x-2)/(x-2)(x+4)