At least 40.There is two sides.Heads and tails.Divide that by two.80/2=40.
The answer for thi question is 2
Answer:
2.67
Step-by-step explanation:
100-92=8
8÷3
![\sqrt[3]{8}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B8%7D%20)
=2.67
Step-by-step explanation:
Given.
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
Take the second equation and subtract 2y to both sides.


Substitute x into the first equation and simplify.




Invert.

Substitute Y into your second equation.



Add -6 to both sides.


Answer:
(6, -3)