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djyliett [7]
3 years ago
15

The probability that a graduate of the Faculty of Finance will defend the diploma “excellent” is 0.6. The probability that he wi

ll defend his diploma “perfectly” and receive an invitation to work at the bank is 0.4. Suppose a student defends a diploma. Find the probability that he will receive an invitation to work in a bank?
Mathematics
1 answer:
Karolina [17]3 years ago
6 0

The probability that he receives an invitation to work in a bank given that he defends his diploma excellently is \mathbf{0. \overline 6}

The known parameters are;

The probability that a graduate of the Faculty of Finance will defend the diploma excellently, P(A) = 0.6

The probability that he will defend perfectly and receive an invitation to work at a bank, P(A∩B) = 0.4

The unknown parameter is;

The probability that the student will receive an invitation from the bank given that the student defend the diploma excellent, \mathbf {P(B \ | \ A)}

The process

\mathbf{ P(B \ | \ A)} is found using the conditional probability formula as follows;

\mathbf {P(B \ | \ A) = \dfrac{P(A \cap B) }{P(A)}}

Plugging in the values, we get;

P(B \ | \ A) = \dfrac{0.4 }{0.6} = \dfrac{2}{3} = 0. \overline 6

The probability that the student will receive an invitation from the bank given that the student defend the diploma excellent, P(B \ | \ A) = \mathbf {0. \overline 6}

Learn more about conditional probability here;

brainly.com/question/10567654

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marishachu [46]

Answer:

The value of x = 14 ...

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Step-by-step explanation:

=> ∠BEC = ∠AED { vertically opposite angles }

∠AED = (7x + 15)°

=> ∠AEB + ∠BEC = 180° { linear pair }

=> ( 5x-3) + ( 7x+15) = 180°

=> 5x -3 + 7x + 15 = 180°

=> 12x + 12 = 180°

=> 12( x +1 ) = 180°

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2 years ago
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Step-by-step explanation:

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3 years ago
43/14 as decimal rounded to nearest hundredth
anzhelika [568]

Answer:The answer would be 3.07.


I divided 43 and 14 and got 3.07143 and then since you said nearest hundredth I just went from left to right and skipped 2 decimals and cut it and kept 3.07.


Hope this helps!



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3 years ago
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