All categories

2 years ago

the radius of the circle increase at a rate of 4 cm ,min how fast is the area of pool increasing when the radius is 5 cm

Mathematics

1 answer:

Norma-Jean [14]2 years ago

3 0

Answer:

40π cm2/ min.

Step-by-step explanation:

First, we should begin with an equation we know relating the area of a circle, the pool, and its radius: A=πr2.

You might be interested in

A circle is to be cut from a 12 ft square board. What will be the area, in square feet, of the inscribed circle? Leave your answ

Kazeer [188]

Answer:

3π sq.feet

Step-by-step explanation:

Area of the square = L²

L is the length of the square

Given

Area of the square = 12 ft square

12 = L²

L = √12

L = 2√3 feet

Since the circle is inscribed in the square, the length of the square will be the diameter of the circle;

Area of the circle = πd²/4

Area of the circle = π(2√3)²/4

Area of the circle = 12π/4

Area of the circle = 3π sq.feet

5 0

3 years ago

1. Slope of line 1: 5/12<br> Slope of line 2: 12/5<br> Parallel<br> Perpendicular<br> Neither

ad-work [718]

Answer:

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

The number of members in the recycling club increased by 15 people. If the club had 12 members previously, what was the percent

ivolga24 [154]

Answer:

125%

Step-by-step explanation:

You divide 15 by 12 and convert to a percentage.

Brainliest?

4 0

3 years ago

If two angles of one triangle equal in measure to two angles of another triangle then the third angles of the triangle

Vika [28.1K]

Answer:

Are also equal

Step-by-step explanation:

Say triangle A has the angles 30 and 60. triangle b also has those angles. Total angle of any triangle is 180 so 180-60-30 = 90 for triangle A and it is also the same for triangle b. Thus 90 = 90 angles are the same.

8 0

2 years ago

Fine length of BC on the following photo.

MrMuchimi

Answer:

$BC=4\sqrt{5}\ units$

Step-by-step explanation:

see the attached figure with letters to better understand the problem

step 1

In the right triangle ACD

Find the length side AC

Applying the Pythagorean Theorem

$AC^2=AD^2+DC^2$

substitute the given values

$AC^2=16^2+8^2$

$AC^2=320$

$AC=\sqrt{320}\ units$

simplify

$AC=8\sqrt{5}\ units$

step 2

In the right triangle ACD

Find the cosine of angle CAD

$cos(\angle CAD)=\frac{AD}{AC}$

substitute the given values

$cos(\angle CAD)=\frac{16}{8\sqrt{5}}$

$cos(\angle CAD)=\frac{2}{\sqrt{5}}$ ----> equation A

step 3

In the right triangle ABC

Find the cosine of angle BAC

$cos(\angle BAC)=\frac{AC}{AB}$

substitute the given values

$cos(\angle BAC)=\frac{8\sqrt{5}}{16+x}$ ----> equation B

step 4

Find the value of x

In this problem

$\angle CAD=\angle BAC$ ----> is the same angle

equate equation A and equation B

$\frac{8\sqrt{5}}{16+x}=\frac{2}{\sqrt{5}}$

solve for x

Multiply in cross

$(8\sqrt{5})(\sqrt{5})=(16+x)(2)\\\\40=32+2x\\\\2x=40-32\\\\2x=8\\\\x=4\ units$

$DB=4\ units$

step 5

Find the length of BC

In the right triangle BCD

Applying the Pythagorean Theorem

$BC^2=DC^2+DB^2$

substitute the given values

$BC^2=8^2+4^2$

$BC^2=80$

$BC=\sqrt{80}\ units$

simplify

$BC=4\sqrt{5}\ units$

7 0

2 years ago