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Ksenya-84 [330]
4 years ago
7

Dorothy is using fabric to cover a photo album the width of the fabric is 5/8 of a yard the area of the fabric is 5/16 square ya

rds what is the length of the fabric
Mathematics
1 answer:
saul85 [17]4 years ago
5 0

For this case we assume that the photo album is rectangular in shape and therefore the fabric too. By definition, the area of a rectangle is given by:

A = a * b

Where:

a: It is the length of the rectangle

b: It is the width of the rectangle

According to the problem data we have to:

b =\frac {5}{8} \yard\\A = \frac {5} {16} \ yards ^ 2

Substituting:

\frac {5} {16} = a * \frac {5} {8}

We clear "a":

a = \frac {\frac {5} {16}} {\frac {5} {8}}\\a = \frac {5 * 8} {16 * 5}\\a = \frac {8} {16}\\a = \frac {1} {2}

Thus, the length of the fabric is \frac {1} {2} yards.

ANswer:

The length of the fabric is\frac {1} {2} yards.

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9514 1404 393

Answer:

  x = y = 12

Step-by-step explanation:

A right triangle with a 45° angle is an isosceles right triangle. That means the legs are both the same length. The side ratios of such a triangle are ...

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The side lengths x and y are both 12 units.

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3 years ago
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Allushta [10]
Check for critical points within the unit ball by solving for when the first-order partial derivatives vanish:
f_x=5yz=0\implies y=0\text{ or }z=0
f_y=5xz=0\implies x=0\text{ or }z=0
f_z=5xy=0\implies x=0\text{ or }y=0


Taken together, we find that (0, 0, 0) appears to be the only critical point on f within the ball. At this point, we have f(0,0,0)=0.

Now let's use the method of Lagrange multipliers to look for critical points on the boundary. We have the Lagrangian

L(x,y,z,\lambda)=5xyz+\lambda(x^2+y^2+z^2-1)

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L_y=5xz+2\lambda y=0
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We then observe that

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5yz+2\left(-\dfrac{15xyz}2\right)x=0\implies5yz(1-3x^2)=0\implies x=\pm\dfrac1{\sqrt3}
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So ultimately, we have 9 critical points - 1 at the origin (0, 0, 0), and 8 at the various combinations of \left(\pm\dfrac1{\sqrt3},\pm\dfrac1{\sqrt3},\pm\dfrac1{\sqrt3}\right), at which points we get a value of either of \pm\dfrac5{\sqrt3}, with the maximum being the positive value and the minimum being the negative one.
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scoray [572]

Answer:

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Step-by-step explanation:

2x - 6 =0

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solve both of these for x

these are your zeros

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