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kiruha [24]
3 years ago
8

What is the value of x?

Mathematics
1 answer:
Tanya [424]3 years ago
3 0

Step-by-step explanation:

19x - 4 = 110 ( alternate Exterior angle )

→ 19x = 110 + 4 = 114

→ x = 114/19

→ x = 6

therefore, value of x is 6°.

HOPE THIS ANSWER HELPS YOU DEAR! TAKE CARE

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The scale factor of the dilation that transforms the triangle is 1/3

Step-by-step explanation:

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3 years ago
PLEASE HELP ME THIS.. I REALLY NEED<br> HELP
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9514 1404 393

Answer:

  5 hours

Step-by-step explanation:

A quick way to look at this is to compare the difference in hourly charge to the difference in 0-hour charge.

The first day, the charge is $3 more than $12 per hour.

The second day, the charge is $12 less than $15 per hour.

The difference in 0-hour charges is 3 -(-12) = 15. The difference in per-hour charges is 15 -12 = 3. The ratio of these is ...

  $15/($3/h) = 5 h

The charges are the same after 5 hours.

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If you write equations for the charges, they will look like ...

  y1 = 15 + 12(x -1)

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Equating these charges, we have ...

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You might notice that the math here is very similar to that described in words, above.

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6 0
3 years ago
Suppose a couple planned to have three children. Let X be the number of girls the couple has.
sesenic [268]

Answer:

a) {GGG, GGB, GBG, BGG, BBG, BGB, GBB, BBB}

b) {0,1,2,3}

c)

P(X=2) = \dfrac{3}{8}

d)

P(\text{3 boys}) = \dfrac{1}{8}

Step-by-step explanation:

We are given the following in the question:

Suppose a couple planned to have three children. Let X be the number of girls the couple has.

a) possible arrangements of girls and boys

Sample space:

{GGG, GGB, GBG, BGG, BBG, BGB, GBB, BBB}

b) sample space for X

X is the number of girls couple has. Thus, X can take the values 0, 1, 2 and 3 that is 0 girls, 1 girl, 2 girls and three girls from three children.

Sample space: {0,1,2,3}

c) probability that X=2

P(X=2)

That is we have to compute the probability that couple has exactly two girls.

\text{Probability} = \displaystyle\frac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}}

Favorable outcome: {GGB, GBG, BGG}

P(X=2) =\dfrac{3}{8}

d) probability that the couple have three boys.

Favorable outcome: {BBB}

P(BBB) = \dfrac{1}{8}

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