Answer:
we need more information
Step-by-step explanation:
Since 100 cents = $1
Then to convert $20 to cents, all you have to do is multiply.
$20 × 100 cents
<em><u>=2000 cents. </u></em>
More examples to try:
Convert $0.10 dollars to cents.
$10 × 100 cents = 1000 cents.
Here is a guild for next time:
100 cents = $1
200 cents = $2
300 cents = $3
400 cents = $4
___ cents = $__
So.....now you can fill in the blanks by yourself. Tell me the answer if possible! :D
~Hope this helped!~
…………………………….is the answer
Answer:
essentially, in these problems, youre finding the square root of each number. the square root should be a decimal thats in between two other numbers, and those will be the integers that the value of the square root is between. unless the value is exactly a number and a half, it will be closer to one integer than the other. the work is below.
square root of:
59= 7.68
68= 8.246
78= 8.83
93= 9.64
104= 10.198
124= 11.14
33= 5.74
185= 13.6
215= 14.66
these are just the square roots. but, as you can see, each number is between two other whole numbers on a number line. So, just write down what those numbers are.
7.68 is between 7 and 8
8.246 is between 8 and 9
8.83 is between 8 and 9
9.64 is between 9 and 10
10.198 is between 10 and 11
11.14 is between 11 and 12
5.74 is between 5 and 6
13.6 is between 13 and 14
14.66 is between 14 and 15
so, we know thw numbers that each decimal is between, but we have to find which one each is cloest to. in order to do that, just know that if the decimal is more than .5 its closer to the larger number, and its its less than .5, its closer to thw smaller number.
7.68 is closer to 8
8.246 is closer to 8
8.83 is closer to 9
9.64 is closer to 10
10.198 is closer to 10
11.14 is closer to 11
5.74 is closer to 6
13.6 is closer to 14
14.66 is closer to 15
<span>A perpendicular bisector of a line segment is a line segment perpendicular to and passing through the midpoint of (left figure). The perpendicular bisector
of a line segment can be constructed using a compass by drawing circles
centered at and with radius and connecting their two intersections.
Hope i helped
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