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2 years ago

Please don't answer if you don't know, please!!

Mathematics

2 answers:

Snezhnost [94]2 years ago

7 0

Answer:

See The Attachment

scZoUnD [109]2 years ago

3 0

Answer:

Refer to the attachment

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AD _____ EC Choose the relationship symbol to make a true statement.

GarryVolchara [31]

The Greator than symbol (>)

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2 years ago

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G is the centroid of triangle ABC.

AleksAgata [21]

Answer:

x = 37
DG = 22
AG = 44
AD = 66

Step-by-step explanation:

We presume your "centroid ratio theorem" tells you that AG = 2·DG, so ...

(x+7) = 2(x -15)

x + 7 = 2x - 30 . . . . eliminate parentheses

37 = x . . . . . . . . . . .add 30-x

Then AG = 37+7 = 44

and DG = 37-15 = 22.

Of course, AD = AG +GD = 44 +22 = 66

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2 years ago

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Calculate the total population increase of South Africa from 2001 Difference You may use the following formula: Increase = 2001

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2 years ago

What is the function f(x) = 2(x + 6), find x if f(x) = 22

lord [1]

Answer:

Step-by-step explanation:

f(x) = 2(x + 6)

f(x) = 22

thereofre we have the equation:

2(x + 6) = 22 use distributive property

2x + 12 = 22 subtract 12 from both sides

2x = 10 divide both sides by 2

x = 5

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2 years ago

) An instructor gives his class a set of 18 problems with the information that the next quiz will consist of a random selection

RSB [31]

Answer:

The probability the he or she will answer correctly is 1.5%

Step-by-step explanation:

In all, there are 18 problems. In this question, the order of which the problems are sorted for the quiz makes no difference. For example, if the question A of the quiz is P1 and question B P2, and question A P2 and question B P1, it is the same thing.

There are 18 problems and 9 are going to be selected. So, there is going to be a combination of 9 elements from a set of 18 elements.

A combination of n elements from a set of m objects has the following formula:

$C_{(m,n)} = \frac{m!}{n!(m-n)!}$

In this question, m = 18, n = 9. So the total number of possibilities is:

$T_{p} = C_{(18,9)} = \frac{18!}{9!(18-9)!} = 48620$

Now we have to calculate the number of desired outcomes. This number is a combination of 9 elements from a set of 13 elements(13 is the number of problems that the student has figured out how to do).

Now, m = 13, n = 9. The number of desired possibilities is:

$D_{p} = C_{(13,9)} = \frac{13!}{9!(13-9)!} = 715$

The probability is the number of desired possibilities divided by the number of total possibilities. So

$P = \frac{715}{48620} = 0.015 = 1.5%$

The probability the he or she will answer correctly is 1.5%

3 0

2 years ago