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Amiraneli [1.4K]
2 years ago
13

Mario kart is mercedes lol

Computers and Technology
2 answers:
anyanavicka [17]2 years ago
6 0

Answer:

facts xD

Explanation:

GREYUIT [131]2 years ago
4 0
It got that amg engine in dat thing!!
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During the course of execution of a program, the processor will increment the contents of the instruction register (program coun
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Bdbdbdhdhdhdhdjdbsbbrvrvrrvrvrvfvfvvfvfvfvfvfhdhdhdhdhdhdhhdududududududuebebbedvdvd I known why ahh it happened
8 0
3 years ago
In 3–5 sentences, describe how technology helps business professionals to be more efficient.
quester [9]

Answer:

Technology helps business professionals, keep more organized, communicate better, and effectively keeps businesses secure. Technology helps keep employee information and business paper work more organized using computers and software; while making it easier to communicate with employee's using e-mail and memo's.

Explanation:

8 0
3 years ago
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Using Module operator, write a java program to print odd number between 0 and 1000​
jolli1 [7]

Answer:

class OddNumber

{

  public static void main(String args[])  

       {

         int n = 1000;  //Store 1000 in Variable n typed integer

         System.out.print("Odd Numbers from 1 to 1000 are:");  // Print headline of output window

         for (int i = 1; i <= n; i++)  //For loop to go through each number till end

          {

            if (i % 2 != 0)  //check if number is even or odd.Not divisible by 2 without reminder means it is odd number

             {

               System.out.print(i + " "); //print odd numbers

             }

          }

       }

}              

5 0
3 years ago
Write a program with a main method that asks the user to enter an array of 10 integers. Your main method then calls each of the
Kay [80]

Answer:

The remaining part of the question is given as follows:

printReverse - a void method that reverses the elements of the array and prints out all the elements in one line separated by commas (see sample output below).

getLargest - an int method that returns the largest value in the array.

computeTwice- a method that returns an array of int which contains 2 times of all the numbers in the array (see the sample output below).

Explanation:

// Scanner class is imported to allow the program receive

// user input

import java.util.Scanner;

// Arrays class is imported to allow the program display the array

// in a pretty way

import java.util.Arrays;

//The class definition

public class Solution {

   // main method is defined which signify beginning of program

  // execution

   public static void main(String[ ] args) {

       // an array is initialized with a size of 10

       int[] array =new int[10];

       // Scanner object scan is defined

       Scanner scan =new Scanner(System.in);

       // A loop is initiated to receive 10 user input to fill the array

       for(int i=0; i < 10; i++){

           System.out.print("Please enter number: ");

           array[i]=scan.nextInt();

       }

       

       // A blank line is print

       System.out.println();

       // printReverse method is called with the received array as

      // argument

       printReverse(array);

       // A blank line is print

       System.out.println();

       // The largest number is printed

       System.out.println("The largest number is: " + getLargest(array));

       // computeTwice method is called to display the array after

      // multiplying each element by 2

       computeTwice(array);

       System.out.println( "The values of the computed twice array is: " );

       // Arrays class is used to print the array in form of a string

      // not object

       System.out.println(Arrays.toString(array));

   }

   

   //printReverse method declared with inputArray as parameter.

   // It has no return type

   public static void printReverse(int[] inputArray){

       System.out.print("Here is the arrray in reverse order: ");

       // A loop goes through the array starting from the end

       // and display each element

       for(int i = (inputArray.length - 1); i >= 0; i--){

           if(i == 0){

               // If the last element, do not append comma

               System.out.print(inputArray[i]);

           } else {

               // If not the last element, do append a comma

               System.out.print(inputArray[i] + ", ");

           }

       }

   }

   

   // getLargest method is declared with inputArray as parameter

   //  it compare each element in the array and return the largest

   public static int getLargest(int[] inputArray){

       // The first element is assumed to be the largest before the

      // loop begin

       int max = inputArray[0];

       for(int i = 1; i < inputArray.length; i++){

           if (inputArray[i] > max){

               max = inputArray[i];

           }

       }

       return max;

   }

   

   // computeTwice is declared with inputArray as parameter

   // it loop through the array and multiply each element by 2

   // it then return a modified array

   public static int[] computeTwice(int[] inputArray){

       for(int i = 0; i < inputArray.length; i++){

           inputArray[i] *= 2;

       }

       return inputArray;

   }

}

8 0
3 years ago
A product/process is referred to as a key Technology during which of the
Rufina [12.5K]

The correct answer is D. Mature Phase

Explanation:

Most products go through four different phases, this includes the emerging phase, the growing phase, the mature phase, and the decline phase. In each of these phases, the product has a different impact on the general market.

In the case of the mature phase, this occurs once the product is established in the market, which means the product is known by many people and is considered as key or necessary. For example, nowadays smartphones are in the mature phase because these are an important part of the market or are key. Moreover, this phase occurs after the product grows in the market, and before it declines. Thus, a product is a key technology during the mature phase.

5 0
3 years ago
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