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Nat2105 [25]
2 years ago
11

Can you help please?

Mathematics
1 answer:
saw5 [17]2 years ago
3 0

Answer:

Step-by-step explanation:

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The volume of a cylinder is 4,019.2 cubic units. If the radius is 8 units, how tall is the cylinder?
AVprozaik [17]
We will be using the formula in looking for the volume of the cylinder which is

V = πr²h

where:

r = radius
h = height
V = volume

but in the problem V and r have values already:
r = 8
V = 4019.2

plug this in the volume equation:

V = πr²h
= 4019.2 = π* 8² * h
= 4019.2 = 64πh
= 4019.2 / 64π = h

so the answer is: h = 4019.2 /201.06193
= 19.99 is the height of the cylinder.


8 0
4 years ago
If i have a forest composed of 25 species of trees, each with a known abundances, how many events are there in the sample space
Vsevolod [243]
There are 25 species of trees, each with a known abundances. The question is how many possible ways to randomly select one tree there are.
We should calculate the number of combinations. Combinations, because we select item/s from a collection. In this case, when we select only one item, the combination is also a permutation. From set of n objects we select r. In our case: n=25, r=1. 
The equation is: n!/r!(n-r)!= 25!/1!*24!=25*24!/24!=25
There are 25 different outcomes (events).
3 0
3 years ago
What is the answer to this multiple choice question?
evablogger [386]

Answer:

All expressions are correct

Step-by-step explanation:

9z+7z = 16 z

We need to find an expression ( or expressions ) that are equal to 16z

6z+3z+ 7z = 16z  Correct

z+8z+7z = 16z   Correct

z*16 = 16z  Correct

21z+ -5z = 16z  Correct

6 0
3 years ago
Find the length of the hypotenuse of an isosceles right triangle whose legs are 1 unit in length.
Kobotan [32]
h =  \sqrt{ 1^{2} + 1^{2} } = \sqrt{1+1} = \sqrt{2}
7 0
3 years ago
Each of these extreme value problems has a solution with both a maximum value and a minimum value. Use Lagrange multipliers to f
tino4ka555 [31]

Answer:

The minimum value of the given function is f(0) = 0

Step-by-step explanation:

Explanation:-

Extreme value :-  f(a, b) is said to be an extreme value of given function 'f' , if it is a maximum or minimum value.

i) the necessary and sufficient condition for f(x)  to have a maximum or minimum at given point.

ii)  find first derivative f^{l} (x) and equating zero

iii) solve and find 'x' values

iv) Find second derivative f^{ll}(x) >0 then find the minimum value at x=a

v) Find second derivative f^{ll}(x) then find the maximum value at x=a

Problem:-

Given function is f(x) = log ( x^2 +1)

<u>step1:</u>- find first derivative f^{l} (x) and equating zero

  f^{l}(x) = \frac{1}{x^2+1} \frac{d}{dx}(x^2+1)

f^{l}(x) = \frac{1}{x^2+1} (2x)  ……………(1)

f^{l}(x) = \frac{1}{x^2+1} (2x)=0

the point is x=0

<u>step2:-</u>

Again differentiating with respective to 'x', we get

f^{ll}(x)=\frac{x^2+1(2)-2x(2x)}{(x^2+1)^2}

on simplification , we get

f^{ll}(x) = \frac{-2x^2+2}{(x^2+1)^2}

put x= 0 we get f^{ll}(0) = \frac{2}{(1)^2}   > 0

f^{ll}(x) >0 then find the minimum value at x=0

<u>Final answer</u>:-

The minimum value of the given function is f(0) = 0

5 0
4 years ago
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