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AnnyKZ [126]
2 years ago
10

DO THE MATH

Mathematics
1 answer:
lesantik [10]2 years ago
4 0

f(p) where p is the price in thousands. f(250) means the average number of days before being sold for $250,000. Lets take a look at the answers and see which fits the best:

1. The house sold for $250,000. (This is what the 250 stands for, but we need to find what f(250) means and not just 250)

2. The house stayed on the market for an average of 250 days before being sold. (Nope, not even close)

3. This is the average number of days the house stayed on the market before being sold for $250,000. (Yes! This seems right, f(250) is the average number of days before being sold for $250,000)

4. The house sold on the market for $250,000 and stayed on the market for an average of 250 days before being sold. (Nope, we are not told anywhere that it takes 250 days to be sold)

This means that our answer has to be 3) This is the average number of days the house stayed on the market before being sold for $250,000.

I hope I've helped! :)

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Please help me, only answer if you know for sure
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Answer:

Step-by-step explanation:

Median: First write in ascending order. If number of data's is odd, median is the middle data.

If number of data's is even, then median = average of n/2th and (n+2)/2th term.

1) 1 , 3 , 5 , 5 , 6

Median = 5

2) 3,4,10,2,1

Ascending order: 1,2,3,4,10

Median = 3

3) 4, 5,7,11

Median = (5+7)/2 = 12/2 = 6

4) 1,1,2,6

Median = (1+2)/2 = 3/2 = 1.5

5) 2,2,3,3,,5,7

Median = 3+3/2 = 6/2 = 3

6)1,2,4,6,7,7

Median = (4+6)/2 = 10/2 = 5

7) 2,2,3,6,7,8

Median = (3+6)/2 = 9/2 = 4.5

8)1,2,3,14,17,18

Median = (3+14)/2 = 17/2 = 8.5

Mean= Sum of all the items÷ number of items

1)Mean = (1+2+3+2)÷4 = 8÷2 = 4

2)Mean=(4+3+2+4+2)÷5 = 15÷5 = 3

3)Mean = (5+4+6+1)÷4 = 16÷4 = 4

4)Mean = (2+5+1+4+7+5)÷6 = 24÷6 = 4

5)Mean =(10+11+9+12+8)÷5=50÷5 = 10

6)Mean = (1 + 2 + (-2)+1+(-2) )÷5 = -2÷5 = -0.4

7)Mean = (4+(-2)+3+(-3)+3)÷5 = 5÷5 = 1

8)Mean = (4+5.5+3+5.5)÷4=18÷4 = 4.5

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2 years ago
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Answer:

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Answer:

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Whereby, the table of values for the quadratic relation from which the second difference is found starts from x = 3, we have;

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