The equilibrium constant of the reaction is 0.323.
Equilibrium constant:
It is expressed as the ratio of concentration of the products to the concentration of reactants. It is represented by K.
The relationship of K with G (Gibbs free energy) is expressed as:
G° = -RTlnK
Here R is the gas constant, T is the temperature.
Calculations:
Convert 25°C to K.
25°C = (25 + 273.15) K
= 298.15 K
Substitute the values in the above expression.
2.8 x 1000 J/mol = -8.314 J/mol.K x 298.15 K x ln(K)
lnK = 2800 J/mol/(-8.314 J/mol.K x 298.15 K)
lnK = -1.13
K = e^-1.13
= 0.323
Learn more about Gibbs free energy here:
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All of them are ionic (positive charge) when bonded with a nonmetal(negative charge). Hydrogen is in Group 1 with the alkali metals but is considered a nonmetal.
Answer:
Mass of 1 mole of copper is 63.83 g.
0.03916 moles of copper atoms have a mass equal to the 2.5 grams of copper penny.
Explanation:
Mass of 1 copper atom,m =
Mass of 1 mole of copper :
=
Mass of 1 mole of copper = 63.83 g
Mass of copper penny = 2.5 g
Atomic mass of copper = 63.83 g/mol
Moles of copper in 2.5 g of copper penny:
0.03916 moles of copper atoms have a mass equal to the 2.5 grams of copper penny.
Answer:
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Explanation: