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4 years ago

What metals generally form ionic bonds

2 answers:

5 0

All of them are ionic (positive charge) when bonded with a nonmetal(negative charge). Hydrogen is in Group 1 with the alkali metals but is considered a nonmetal.

const2013 [10]4 years ago

5 0

Group 1,group 2 and group 3 metals form ionic bonds since they donate electrons.

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While dinner was cooking, Rachel noticed that there was steam coming from a pot of boiling water. Which of the following stateme

Alex777 [14]

Answer:

There is a physical change as the water is evaporating, producing a gas.

7 0

3 years ago

The electronegativity values of fluorine, oxygen, and hydrogen are compared in the table. Comparison of Electronegativity Elemen

Dvinal [7]

The hydrogen bonding in H₂O is stronger than that of HF

Explanation:

Hydrogen bonds are special dipole-dipole attraction in which electrostatic attraction is established between hydrogen atom of one molecule and the electronegative atom of a neighboring molecule.

The strength of hydrogen bonds depends on the how electronegative an atom is.
Electronegativity refers to the tendency of an atom to gain electrons.
The higher the value, the higher the tendency.
This why oxygen with a higher electronegativity will form a stronger hydrogen bond with hydrogen compared to fluorine.

Learn more:

hydrogen bond brainly.com/question/12408823

#learnwithBrainly

4 0

3 years ago

If you start with 6 mol of nitrogen gas (N2+) what mass (g) of ammonia (NH4) will be produced?

Yanka [14]

Answer:

204g of NH3

Explanation:

The balanced equation for the reaction is given below:

N2 + 3H2 —> 2NH3

Next, we shall determine the number of mole NH3 produced by reacting 6moles of N2. This is illustrated below:

From the balanced equation above,

1 mole of N2 reacted to produce 2 moles of NH3.

Therefore, 6 moles of N2 will react to produce = 6 x 2 = 12 moles of NH3.

Finally, we shall convert 12 moles of NH3 to grams. This is illustrated below:

Number of mole of NH3 = 12 moles.

Molar mass of NH3 = 14 + (3x1) = 17g/mol

Mass of NH3 =..?

Mass = mole x molar mass

Mass of NH3 = 12 x 17

Mass of NH3 = 204g.

Therefore, 204g of NH3 will be produced from the reaction.

3 0

3 years ago

A certain element X has four isotopes. 4.350% of X has a mass of 49.94605 amu. 83.79% of X has a mass of 51.94051 amu. 9.500% of

sesenic [268]

Answer: The average atomic mass of the element X is 51.99592 amu

Explanation:

Mass of isotope 1 = 49.94605 amu

% abundance of isotope 1 = 4.350% = $\frac{4.350}{100}=0.0435$

Mass of isotope 2 = 51.94051 amu.

% abundance of isotope 2 = 83.79% = $\frac{83.79}{100}=0.8379$

Mass of isotope 3 = 52.94065 amu.

% abundance of isotope 2 = 9.500% = $\frac{9.500}{100}=0.095$

Mass of isotope 4 = 53.93888 amu.

% abundance of isotope 2 = 2.360% = $\frac{2.360}{100}=0.0236$

Formula used for average atomic mass of an element :

$\text{ Average atomic mass of an element}=\sum(\text{atomic mass of an isotopes}\times {{\text { fractional abundance}})$

$A=(49.94605\times 0.0435)+(51.94051 \times 0.8379)+ (52.94065\times 0.095)+(53.93888\times 0.0236)$

$A=51.99592amu$

Therefore, the average atomic mass of the element X is 51.99592 amu

5 0

3 years ago

A 10.0 milliliter sample of NaOH (aq) is neutralized by 40.0 milliliters of 0.50 M HCl. What is the molarity of the NaOH (aq)?

garik1379 [7]

$NaOH_{(aq)} + HCl_{(aq)} ------\ \textgreater \ NaCl_{(aq)} + H_{2} O_{(l)}$

moles of HCl = (molarity) * (volume)
= $0.50 mol / dm^{3} * 0.040 dm^{3}$
= 0.02 mol

mole ratio of NaOH : HCl according to the equation is 1 : 1
∴ mol of NaOH = mol of HCl
= 0.02mol

Since volume of NaOH is 0.010 $dm^{3}$

then molarity of NaOH = $\frac{moles}{volume}$
= $\frac{0.02 mol}{0.010 dm^{3}}$
= $2.0 mol / dm^{3} OR 2.0 M$

Note:
1) $mol/ dm^{3}$ is the same as M
2) I converted the ml to l then to $dm ^{3}$

6 0

3 years ago

Read 2 more answers