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Answer:
y = 10/9x + 8/3
Step-by-step explanation:
A line that is perpendicular to y = -9/10x - 10 has a slope that is the negative reciprocal. Therefore:
-9/10 --> 10/9. This is the slope of line q.
Use the formula y = mx + b where:
m = slope
x = x coordinate of point
y = y coordinate of point.
-4 = 10/9(-6) + b
-4 = -60/9 + b
Create a common denominator:
-36/9 = -60/9 + b
24/9 = b
Simplify:
b = 8/3.
Rewrite the equation:
y = 10/9x + 8/3
Answer:
d = -1/3, 0
Step-by-step explanation:
Subtract the constant on the left, take the square root, and solve from there.
(6d +1)^2 + 12 = 13 . . . . given
(6d +1)^2 = 1 . . . . . . . . . .subtract 12
6d +1 = ±√1 . . . . . . . . . . take the square root
6d = -1 ±1 . . . . . . . . . . . .subtract 1
d = (-1 ±1)/6 . . . . . . . . . . divide by 6
d = -1/3, 0
_____
Using a graphing calculator, it is often convenient to write the function so the solutions are at x-intercepts. Here, we can do that by subtracting 13 from both sides:
f(x) = (6x+1)^ +12 -13
We want to solve this for f(x)=0. The solutions are -1/3 and 0, as above.
Answer:
Right tailed test
Step-by-step explanation:
The null hypothesis is:
The alternative hypothesis is:
This is a right-tailed test since the alternative hypothesis is greater than 30
Suppose the level of significance is 0.05 and we are given a p-value less than 0.05.
Then, we reject the null hypothesis.
<span>Assuming the reaction is of 1st order, we can
start using the formula for rate of 1st order reaction:</span>
dN / dt = k * N
Rearranging,
dN / N = k dt
Where N = amount of sample, k = rate constant, t = time
Integrating the equation from N = Ni to Nf and t = ti to
tf will result in:
ln (Nf / Ni) = k (tf – ti)
Since k is constant, we can equate to situations.
Situation 1 is triple in size every days, situation 2 is after 20 days.
ln (Nf / Ni) / (tf – ti) = k
ln (3Ni / Ni) / 4 = ln (Nf / 40) / 20
Calculating for Nf,
<span>Nf =
9,720 bacteria </span>