The correct answer to this open question is the following.
During this pandemic moments that students have to stay at home and taking classes, I would use the proper hardware to teach good video classes. Of course, a good computer or lap tot with modern hardware capacities such as "intel Pentium" or higher. A good and high-speed internet connection will help me to efficiently use all the tools and educational apps such as the one needed to teach video class. These are google meet and zoom.
I will use the following tools to reach all pupils. First, the classroom of Google to have all the homework information on one site. I would use Google Drive to store all the information and evidence of the semester. Another good tool is Canva, for the students to elaborate all their infographics needed to do homework. For better school presentations I would also use "gneally," a good presentation system that has room for a lot of animation.
Answer:
1.6 cups
Explanation:
Let's make a proportion using the following set up.
cups of sugar/batches=cups of sugar/batches
We know that 0.4 cups of sugar are needed for 1 batch of cookies. We don't know how many cups of sugar are needed for 4 batches. Therefore, we can say that x cups of sugar are needed for 4 batches.
0.4 cups of sugar/1 batch=x cups of sugar/4 batches
0.4/1=x/4
We want to find out what x (cups of sugar for 4 batches) is. In order to do this, we have to get x by itself. Perform the opposite of what is being done to the equation. Keep in mind, everything done to one side, has to be done to the other.
x is being divided by 4. The opposite of division is multiplication. Multiply both sides of the equation by 4.
4*(0.4/1)=(x/4)*4
4*(0.4/1)=x
4*0.4=x
1.6=x
Add appropriate units. IN this case, the units are cups.
x=1.6 cups
4 batches of cookies will require 1.6 cups of sugar.
From the calculations carried out , we can see that the molar solubility of Al(OH)3 is 8.6 x 10^-12 M
<h3>What is solubility?</h3>
The term solubility refers to the amount of substance that dissolves in a solution measured in moles per liter.
From the question we have initial [Al+3] = 0.05 M
Setting up an ICE table:
Al(OH)3(s) → Al3+ + 3OH-
I 0.05 0
C +x +3x
E 0.05+x 3x
Know that;
Ksp = [Al3+] [OH-]^3
Ksp = 1.3 x 10^-33
So;
[Al3+] = (0.05+X) and [OH-]^3 = 3X
If x = molar solubility of Al(OH)3
Then:
1.3 x 10^-33 = (0.05 + X) (3X)^3 by solving for X
x = 8.6 X 10^-12 M
Learn more about Ksp: brainly.com/question/4736767
