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2 years ago

Determine the molar solubility of al(oh)3 in a solution containing 0. 05 m alcl3. Ksp for al(oh)3 is 1. 3 × 10-33.

SAT

1 answer:

Mariulka [41]2 years ago

3 0

From the calculations carried out , we can see that the molar solubility of Al(OH)3 is 8.6 x 10^-12 M

<h3>What is solubility?</h3>

The term solubility refers to the amount of substance that dissolves in a solution measured in moles per liter.

From the question we have initial [Al+3] = 0.05 M

Setting up an ICE table:

Al(OH)3(s) → Al3+ + 3OH-

I 0.05 0

C +x +3x

E 0.05+x 3x

Know that;

Ksp = [Al3+] [OH-]^3

Ksp = 1.3 x 10^-33

So;

[Al3+] = (0.05+X) and [OH-]^3 = 3X

If x = molar solubility of Al(OH)3

Then:

1.3 x 10^-33 = (0.05 + X) (3X)^3 by solving for X

x = 8.6 X 10^-12 M

Learn more about Ksp: brainly.com/question/4736767

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3 years ago

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If the pool is to be 24 ft on each side, what is the length of one side of the hot tub? 4 ft 4. 8 ft 6 ft 7. 2 ft.

riadik2000 [5.3K]

Based on the information given the length of one side of the hot tub is 4. 8 ft.

<h3 /><h3>Length:</h3>

Using this formula

Length=B prime C prime length/Scale factor

Where:

B prime C prime length=24 feet

Scale Factor=5

Let plug in the formula

Length=24ft/5

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2 years ago

Factor the expression into an equivalent form 12y^2-75.

elena-14-01-66 [18.8K]

Hello oddworld7836!

$\huge \boxed{\mathbb{QUESTION} \downarrow}$

Factor the expression into an equivalent form 12y² - 75.

$\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}$

$12 y ^ { 2 } - 75$

By observing the expression, we can see that, 3 is the only common factor in both the terms of the expression. So, take the common factor 3 out.

$12 y ^ { 2 } - 75 \\ = 3\left(4y^{2}-25\right)$

Now, look at (4y² - 25). They don't have any common factors but they appear in the form of the algebraic identity ⇨ a² - b² = (a + b) (a - b). Here,

a² = 4, a = 2 (√a² = ✓4 = 2)
b² = 25, b = 5 (√b² = ✓25 = 5)

So, the (4y² + 25) becomes...

$(4 {y}^{2} - 25) \\ = \left(2y-5\right)\left(2y+5\right)$

Now, bring the 3 (common factor) & rewrite the complete expression.

$12 y ^ { 2 } - 75 \\ = \boxed{ \boxed{ \bf \: 3\left(2y-5\right)\left(2y+5\right) }}$

We can't further simplify it. Also, remember that the simplified form of an expression is equivalent to the expression. So, 3 (2y - 5) (2y + 5) is equivalent to 12y² - 75.

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3 years ago

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Licensees can rely on the statements made by a seller (Seller Disclosure Statement), unless the licensee has reason to believe the information isn't true: True.

<h3>What is a Seller Disclosure Statement?</h3>

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In Real Estate, licensees can rely on the statements that are made by a seller such as in a Seller Disclosure Statement, unless the licensee has reason to believe the information isn't true.

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