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UkoKoshka [18]
3 years ago
9

Simplify square root of negative 121. −11i 11i −11 11

Mathematics
1 answer:
Nesterboy [21]3 years ago
3 0

Answer:  B. 11i

Step-by-step explanation: Have a nice day!✌️

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Makovka662 [10]

Answer:

<h3>2.squareroot 85</h3>

Step-by-step explanation:

<h2>#carry on learning</h2><h2>#mark branlits</h2>
6 0
3 years ago
Fatima writes down three square numbers.
nekit [7.7K]

Answer:

10

Step-by-step explanation:

Fatima wrote down 3 square numbers

since we don't know the three square we will represent it by any variable (X)

3x=30

so you divide both sides by 3

so we have 3x/3=30/3=10

therefore the answer is 10

8 0
3 years ago
Can you please help with this math?&gt;&gt;
goblinko [34]

x = 16 x sin(60) = 8sqrt(3)

 answer is B.

6 0
3 years ago
Read 2 more answers
Substitution for:<br> X-5y=10<br> 2x-10y=20
sergey [27]
Since you need an isolated variable to use the substitution method, we need to re-arrange one of the equations. This will probably be easiest to do with the first one.
Add 5y to both sides of the first equation.
x=10+5y
Now, in the second equation, put in 10+5y in any spot that has an x.
2(10+5y)-10y=20
Distribute the 2 to both numbers in the parenthesis.
20+10y-10y=20
Combine like terms.
20=20
This means that the two equations are actually the same. You can see this if you multiply the whole first equation by 2
2(x-5y=10)
2x-10y=20, which is the same as the second equation. Therefore, the two equations are actually the same one.
5 0
3 years ago
A well-mixed cookie dough will produce cookies with a mean of 66 chocolate chips apiece. What is the probability of getting a co
sp2606 [1]

Answer:

0.7262

Step-by-step explanation:

Let random variable = X

Probability of getting a cookie with at least 55 chips:

P(55≤ X ≤78), where X1 = 55 and X2 = 78

Let mean, U = 66 and  standard deviation, S.D. = 10

Let Z = X - U/S.D; Z1 = X1 - U/S.D and Z2 = X2 - U/S.D

Z1 = 55 - 66/10 = - 1.1

Z2 = 78 - 66/10 = 1.2

P(X1≤ X ≤ X2) = P(X1 -U/S.D ≤ X - U/S.D ≤ X2 - U/S.D)

P(Z1 ≤ Z ≤ Z2) = P(0 ≤ Z ≤ Z1) + P(0 ≤ Z ≤ Z2)

Hence, (55 ≤ X ≤ 78) = P( - 1.1 ≤ Z ≤ 1.2)

∴ P(-1.1 ≤ Z ≤ 1.2) = P(0 ≤ Z ≤ 1.1) + (0 ≤ Z ≤ 1.2)

=   0.3413 + 0.3849 = 0.7262

6 0
3 years ago
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