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2 years ago

Answer these questions

Mathematics

1 answer:

fgiga [73]2 years ago

5 0

Answer:

y = 5

Step-by-step explanation:

first you subtract 5y from itself and from 7y

then you'll get: 2y + 2 < 12

then subtract the 2 from itself and from the 12

that will give you: 2y < 10

then just divide the 2 from itself and that eliminates the 2 but keeps the y, and divide the 10 by the 2

that'll give you y = 5

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What is the multiplicative inverse of -1/5?

luda_lava [24]

Answer:

-5/1

Step-by-step explanation:

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3 years ago

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PLEASE, ANSWER WILL GIVE BRAINLIEST

balu736 [363]

0.30 • 18 = 5.4
0.30 • 40 = 12
0.30 • 9 = 2.7
0.30 • 70 = 21
0.30 • 48 = 14.4
0.30 • 26 = 7.8
0.30 • 14 = 4.2
Add the sums together which would be 67.5
Subtract $100 from $67.5 and that would be $32.5

Answer: $32.50 change

7 0

3 years ago

Diego was trying to write (5^2)^4 with a single exponent and wrote (5^2)^4=5^2+^4=5^6. What should the answer be? Explain Diego'

o-na [289]

Answer:

5^8

Step-by-step explanation:

Diego added the exponents. This was an error. If he was simplifying

5^2 × 5^4, then he could add the exponents and get a correct answer. But his problem had a power raised to a power. In this case, you multiply the exponents to simplify.

(5^2)^4 means

5^2×5^2×5^2×5^2

which is

5×5×5×5×5×5×5×5

which is 5^8.

4 0

2 years ago

Suppose a certain computer virus can enter a system through an email or through a webpage. There is a 40% chance of receiving th

DedPeter [7]

Answer:

P = 0.42

Step-by-step explanation:

This probability problem can be solved by building a Venn like diagram for each probability.

I say that we have two sets:

-Set A, that is the probability of receiving this virus through the email.

-Set B, that is the probability of receiving it through the webpage.

The most important information in these kind of problems is the intersection. That is, that he virus enters the system simultaneously by both email and webpage with a probability of 0.17. It means that $A \cap B$ = 0.17.

By email only

The problem states that there is a 40 chance of receiving it through the email. It means that we have the following equation:

$A + (A \cap B) = 0.40$

$A + 0.17 = 0.40$

$A = 0.23$

where A is the probability that the system receives the virus just through the email.

The problem states that there is a 40% chance of receiving it through the email. 23% just through email and 17% by both the email and the webpage.

By webpage only

There is a 35% chance of receiving it through the webpage. With this information, we have the following equation:

$B + (A \cap B) = 0.35$

$B + 0.17 = 0.35$

$B = 0.18$

where B is the probability that the system receives the virus just through the webpage.

The problem states that there is a 35% chance of receiving it through the webpage. 18% just through the webpage and 17% by both the email and the webpage.

What is the probability that the virus does not enter the system at all?

So, we have the following probabilities.

- The virus does not enter the system: P

- The virus enters the system just by email: 23% = 0.23

- The virus enters the system just by webpage: 18% = 0.18

- The virus enters the system both by email and by the webpage: 17% = 0.17.

The sum of the probabilities is 100% = 1. So:

P + 0.23 + 0.18 + 0.17 = 1

P = 1 - 0.58

P = 0.42

There is a probability of 42% that the virus does not enter the system at all.

5 0

3 years ago

Can someone do this for me thanks ok bye

Dvinal [7]

Answer:

log2 10 = 3x

Step-by-step explanation:

Basic Logarithm Tenets

7 0

3 years ago

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