Answer:
200
Step-by-step explanation:
1/2x + 1 = 2/3x
1/2x - 2/3x = -1
-x/6 = -1
x = 6
Hope this helps!
Answer:
The range of the function are the values of height which are from 3, 4, 5, ..., 50
Step-by-step explanation:
The given parameters are;
The height at which the ball is caught = 5 feet
The height at which the ball was hit = 3 feet
The maximum height reached by the ball = 50 feet
The height of the ball given as a function of time is f(t) s = u·t - 1/2·g·t²
Where;
s = 50 feet
g = 9.81 m/s²
Therefore, we have;
50 = u·t - 1/2 × 9.81 × t²
50 = u·t - 4.905 × t²
Therefore, the range are obtainable values for f(t) which range from 3 to 50.
Short Answers:
Answer for part A: Given
Answer for part B: Angle A = Angle D (not sure why this isn't in word bank?)
Answer for part C: ASA
Answer for part D: BC = EF
Answer for part E: CPCTC
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Explanations:
Part A:
AB = DE is given at the very top of the problem. So we simply say "given". We always repeat what we are given at the very start of the proof. You can see this for lines 1 through 3, which are repeating the three givens.
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Part B:
The three givens are:
AB = DE
angle A = angle D
angle B = angle E
the first and last of this trio is used (for statements 1 and 3 respectively). So the only thing left is "angle A = angle D"
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Part C:
We're using ASA (angle side angle) because we're given two pairs of congruent angles. The side for each triangle is between the two angles. See the attached diagram for more info.
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Part D:
For any proof, you will ALWAYS have the last statement be the thing you want to prove. In this case, we want to prove BC = EF.
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Part E:
CPCTC stands for "Corresponding Parts of Congruent Triangles are Congruent"
If the two whole triangles are congruent, then the smaller corresponding parts that make up the triangles must be congruent as well.
We are given that it takes 7 joules of heat to raise the
temperature of the bar by 1°C. Therefore this means that the heating capacity Cp
is:
Cp = 7 J / °C
The formula for the amount of heat required is:
heat = Cp (Tf – Ti)
where Ti is initial temperature = 25°C, and Tf is the
final temperature
When Tf = 26°C
heat = 7 (26 – 25) = 7 J
When Tf = 27°C
heat = 7 (27 – 25) = 14 J
When Tf = 28°C
heat = 7 (28 – 25) = 21 J
When Tf = 29°C
heat = 7 (29 – 25) = 28 J
When Tf = 30°C
heat = 7 (30 – 25) = 35 J
When Tf = 35°C
heat = 7 (35 – 25) = 70 J