The x intercept occurs when y = 0.
0=(x+2)^2 - 1
1=(x+2)^2
Take the square root of both sides. Note that the sqrt of 1 is 1. Then solve for x.
1=x+2
-1=x
The x intercept is -1.
The y intercept occurs when x=0.
y=(0+2)^2 - 1
y=2^2 -1
y=4-1
y=3
The y intercept is 3.
Now, to find the vertex...
This parabola is currently in a format called the vertex form, which is:
f(x) = (x-h)^2 + k
where (h, k) is the vertex.
Therefore, the vertex is (-2, -1).
This is quite easy, but anyway:
In order, they are
3, 4, 4, 5, 5, 5, 5, 7, 7
7 - 3 = 4
4 would be the range
Answer:
[ - 6 , 6 ]
Step-by-step explanation:
This is because the value of f(t) for x values only ranges from -6 to 6.
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Answer: perpendicular lines
Step-by-step explanation:
look up "Two straight lines that intersect at a right angle"
Answer:
2.64
Step-by-step explanation:
- 13.20 × 1 = 13.20
- 13.20 ÷ 5 = 2.64
