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jek_recluse [69]
3 years ago
11

Examine the system of equations.

Mathematics
2 answers:
tester [92]3 years ago
7 0

Answer:

4,-3

Step-by-step explanation:

Zigmanuir [339]3 years ago
5 0

The answer is 4,-3

Irfcdxsaacd d

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How many 1/2 cup servings are in a box of oatmeal that contains 6 3/4
anzhelika [568]

6 and 3/4 divided by 1/2

27/4 divided by 1/2

27/4 * 2/1 = 27/2 = 13 and 1/2

7 0
3 years ago
Hàm số nào là hàm lẻ<br> A sin^2 x+1 B cot^3x C tn3x cotx d cosx
Sedaia [141]
{(sin (x))^2A(csc(x))^3(cos))3B+(-3x)
{cot (dx) cos (x)
6 0
3 years ago
In a parking lot there are totally 70 vehicles, cars and motorcycles. all together they've got 258 wheels. how many cars are the
docker41 [41]
1 car - 4 wheels
1 motorcycle - 2 wheels

x - number of cars
y - number of motorcycles

so, there are 70 vehicles: x + y = 70
and all togeather they've got 258 wheels: 4*x + 2*y = 258
because each car has 4 wheels, so all car wheels = 4*x,
likewise 2*y for motorcycles

x + y = 70  /* 4
4 x + 2y = 258

4 x + 4 y = 280  (R1)
4 x + 2y = 258    (R2)

2y = 22  /:2      it is R1 - R2
x = 70 - y

y = 11    /motorcycles
x = 70 - 11 = 59  /cars

check:
59 + 11 = 70  ok
59 * 4 + 11 * 2 = 236 + 22 = 258  ok
5 0
3 years ago
Which is the best estimate for the average rate of change for the quadratic function graph on the interval 0 ≤ x ≤ 4?
tatuchka [14]

Answer:

The best estimate for the average rate of change is -2

Step-by-step explanation:

we know that

the average rate of change using the graph is equal to

\frac{f(b)-f(a)}{b-a}

In this problem we have

f(a)=f(0)=0  

f(b)=f(4)=-8

a=0

b=4

Substitute

\frac{-8-0}{4-0}=-2

4 0
3 years ago
Read 2 more answers
You are in charge of planning a reunion party for your high school alumni. The food will cost $12 per person. The rental fee for
castortr0y [4]

Answer:

$3820 total, $32 per alumnus.

Step-by-step explanation:

The total cost will be 12\times120+650+730+1000=3820

Each alumnus pays \frac{3820}{120} =31\frac{5}{6}

Rounding to nearest whole number = $32 per alumnus.

5 0
2 years ago
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