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2 years ago

Can u answer this plz thanks

Mathematics

1 answer:

maks197457 [2]2 years ago

5 0

Answer: 3/4 of 8 just means 3/4 x 8, which is 6 miles. Do the same with 3/5 x 10, which is also 6 miles. Therefore both of them walked the same distance. Please mark me brainliest!

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A dozen eggs cosy $1.32 at the grocery store .how much profit would a restaurant make if the sold 1 scramble egg for 99 cent

tatuchka [14]

What we know: A dozen costs 1.32; there are 12 in a dozen.
What we need to know: How much a restaurant makes selling 1 egg at 0.99.
First, find the value of one egg; you can do that by dividing the total cost (1.32) by the amount (12):
1.32 / 12 = 0.11 <-- The cost per egg is 11 cents. To find the profit of the restaurant, just subtract the cost from the price they sell it for:
0.99 - 0.11 = 0.88 <-- The profit the restaurant makes per egg is 88 cents.

Hope this helps.

5 0

2 years ago

What is the percentage decrease if an item has dropped from $115 to $46

Sav [38]

Answer: 60% decrease

Step-by-step explanation:

Look at the attachment

4 0

3 years ago

A manufacturer of matches randomly and independently puts 23 matches in each box of matches produced. The company knows that one

d1i1m1o1n [39]

Answer:

0.9855 or 98.55%.

Step-by-step explanation:

The probability of each individual match being flawed is p = 0.008. The probability that a matchbox will have one or fewer matches with a flaw is the same as the probability of a matchbox having exactly one or exactly zero matches with a flaw:

$P(X\leq 1)=P(X=0)+P(X=1)\\P(X\leq 1)=(1-p)^{23}+23*(1-p)^{23-1}*p\\P(X\leq 1)=(1-0.008)^{23}+23*(1-0.008)^{23-1}*0.008\\P(X\leq 1)=0.8313+0.1542\\P(X\leq 1)=0.9855$

The probability that a matchbox will have one or fewer matches with a flaw is 0.9855 or 98.55%.

8 0

3 years ago

Which line is a graph of the equation x = 6? Identify the intercept.

Step2247 [10]

Correct answer is D.

Line x = a is parallel with y-axis and passes through the point (a,0).

So our line is parallel with y-axis and passes through the point (6,0).

3 0

2 years ago

Read 2 more answers

Problem PageQuestion

krok68 [10]

Answer:

Jennifer's height is 63.7 inches.

Step-by-step explanation:

Let X = heights of adult women in the United States.

The random variable X is normally distributed with mean, μ = 65 inches and standard deviation σ = 2.4 inches.

To compute the probability of a normal random variable we first need to convert the raw score to a standardized score or z-score.

The standardized score of a raw score X is:

$z=\frac{X-\mu}{\sigma}$

These standardized scores follows a normal distribution with mean 0 and variance 1.

It is provided that Jennifer is taller than 70% of the population of U.S. women.

Let Jennifer's height be denoted by x.

Then according to the information given:

P (X > x) = 0.70

1 - P (X < x) = 0.70

P (X < x) = 0.30

⇒ P (Z < z) = 0.30

The z-score related to the probability above is:

z = -0.5244

*Use a z-table.

Compute the value of x as follows:

$z=\frac{X-\mu}{\sigma}$

$-0.5244=\frac{x-65}{2.4}$

$x=65-(0.5244\times 2.4)$

$=63.7414\\\approx63.7$

Thus, Jennifer's height is 63.7 inches.

3 0

2 years ago