Answer:
Grouping and then use the common factor. Therefor the answer is 6(2p+5)
Step-by-step explanation:
I hope this helps.
It is no solution, bc the answer is (0,0)
Given CD is an altitude such that AD=BC , AB=3 cm and CD= √2 cm.
Let AD=x, Since given AB=3
AD+DB=3
x+DB = 3
DB = 3-x
Since ΔBCD is rght angle triangle, let's apply Pythagoras theorem
![BC^{2} = DB^{2} +CD^{2}](https://tex.z-dn.net/?f=BC%5E%7B2%7D%20%3D%20DB%5E%7B2%7D%20%2BCD%5E%7B2%7D)
![BC^{2} = (3-x)^{2} +(\sqrt{2} )^{2}](https://tex.z-dn.net/?f=BC%5E%7B2%7D%20%3D%20%283-x%29%5E%7B2%7D%20%2B%28%5Csqrt%7B2%7D%20%29%5E%7B2%7D)
![BC^{2} =(3-x)^{2} +2](https://tex.z-dn.net/?f=BC%5E%7B2%7D%20%3D%283-x%29%5E%7B2%7D%20%2B2)
Since given AD=BC,let us plugin BC=x in above step.
![x^{2} =(3-x)^{2} +2](https://tex.z-dn.net/?f=x%5E%7B2%7D%20%3D%283-x%29%5E%7B2%7D%20%2B2)
![x^{2} =9-6x+x^{2} +2](https://tex.z-dn.net/?f=x%5E%7B2%7D%20%3D9-6x%2Bx%5E%7B2%7D%20%2B2)
6x=11
x=![\frac{11}{6}](https://tex.z-dn.net/?f=%5Cfrac%7B11%7D%7B6%7D)
Now we know AD=x=
and given CD=√2.
Let us apply Pythagoras theorem for ΔACD
![AC^{2} =AD^{2} +DC^{2}](https://tex.z-dn.net/?f=AC%5E%7B2%7D%20%3DAD%5E%7B2%7D%20%2BDC%5E%7B2%7D)
![AC^{2} = (\frac{11}{6} )^{2} +(\sqrt{2} )^{2}](https://tex.z-dn.net/?f=AC%5E%7B2%7D%20%3D%20%28%5Cfrac%7B11%7D%7B6%7D%20%29%5E%7B2%7D%20%2B%28%5Csqrt%7B2%7D%20%29%5E%7B2%7D)
![AC^{2} =\frac{193}{36}](https://tex.z-dn.net/?f=AC%5E%7B2%7D%20%3D%5Cfrac%7B193%7D%7B36%7D)
= 2.315cm
The First One
The Third One
The Forth One
The others result in a lower number than what they are supposed to be. The 3 correct ones end with the exact number of the equations solution number.