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hram777 [196]
4 years ago
13

Really need your help

Mathematics
1 answer:
Crank4 years ago
3 0

1: (n + 10) +5

2: (n - 7) x 8

3: (n ÷ 3) -1

4: ([n - 8] x 6) - 10

5: (n - 1) - (2n)

6: [n x (-n)] + 7

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A parallelogram has sides lengths of 7inches and 11inches find the perimeter
MissTica

Answer:

36 inches

Step-by-step explanation:

7 * 2 = 14

11 * 2 = 22

14 + 22 = 36

5 0
4 years ago
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M is the midpoint of DE. If MD = 4x - 6 and ME = 3x + 2, find the length of DE.
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The length of the de uwb
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What is the fraction 19/30 written as a decimal
Ahat [919]

Answer:

19/30 written as decimal is 0.63333

Step-by-step explanation:

Divide numerator by denominator of fraction.

4 0
4 years ago
I don’t know how to solve this
Lady_Fox [76]

Answer:

\theta =2\pi k,\ \ k\in Z\ \\\text{or}\ \\\theta=-\dfrac{2\pi}{3}+2\pi k,\ \ k\in Z

Step-by-step explanation:

Given:

\cos \theta-\sqrt{3}\sin \theta=1

Divide this equation by 2:

\dfrac{1}{2}\cos \theta-\dfrac{\sqrt{3}}{2}\sin \theta=\dfrac{1}{2}

Note that

\cos \dfrac{\pi }{3}=\dfrac{1}{2}\\ \\\sin \dfrac{\pi }{3}=\dfrac{\sqrt{3}}{2}

So, the previous equation is

\cos \dfrac{\pi}{3}\cdot \cos \theta-\sin \dfrac{\pi}{3}\cdot \sin \theta=\dfrac{1}{2}

Remind that

\cos x\cos y-\sin x\sin y=\cos (x+y),

then

\cos \left(\dfrac{\pi}{3}+\theta\right)=\dfrac{1}{2}

The solution of this equation is

\dfrac{\pi}{3}+\theta=\pm \arccos \dfrac{1}{2}+2\pi k,\ \ k\in Z\\ \\\dfrac{\pi}{3}+\theta=\pm \dfrac{\pi}{3}+2\pi k,\ \ k\in Z\\ \\\theta =2\pi k,\ \ k\in Z\ \text{or}\ \theta=-\dfrac{2\pi}{3}+2\pi k,\ \ k\in Z

8 0
3 years ago
What are all the angles in math
Serjik [45]

if u mean what i think u mean the angles are the following...

acute

obtuse

right

straight!

4 0
3 years ago
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