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LekaFEV [45]
3 years ago
9

Find zeroes of quadratic polynomial p(x) = x2 -3x - 4.​

Mathematics
1 answer:
MAVERICK [17]3 years ago
4 0

Here is ur answer

<em>-</em><em> </em><em>BRAINLIEST</em><em> answerer</em>

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How to <br> Write <br> 3/9<br> in simplest form.
White raven [17]
To write it in simplest form, you must find a common factor.

In \frac{3}{9}, 3 is a factor of both 3 and 9

3÷3=1 and 9÷3=3

So \frac{3}{9} =  \frac{1}{3}

\frac{1}{3} is your answer in simplest form.
3 0
3 years ago
Matt is baking cookies.
artcher [175]
I am certain it is

200g butter
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5 0
3 years ago
Please also should work
DedPeter [7]

Answer:

B 2 < x < 6

Step-by-step explanation:

six times an integer is between 12 and 36.  Between does not include so we use <   not ≤

12 < 6x < 36

Divide all sides by 6

12/6 < 6x/6 < 36/6

2 < x < 6

7 0
4 years ago
Find the cross product of <img src="https://tex.z-dn.net/?f=-%20%5Cfrac%7B3%7D%7B4%7Dv" id="TexFormula1" title="- \frac{3}{4}v"
dsp73
For any scalars c_1,c_2, we have

c_1\mathbf v\times c_2\mathbf w=c_1c_2\mathbf v\times\mathbf w

So

\left(-\dfrac34\mathbf v\right)\times\left(-\dfrac12\mathbf w\right)=\dfrac38\mathbf v\times\mathbf w

We have

\mathbf v\times\mathbf w=\begin{vmatrix}\mathbf i&\mathbf j&\mathbf k\\-2&12&-3\\-7&4&-6\end{vmatrix}
=\begin{vmatrix}12&-3\\4&-6\end{vmatrix}\mathbf i-\begin{vmatrix}-2&-3\\-7&-6\end{vmatrix}\mathbf j+\begin{vmatrix}-2&12\\-7&4\end{vmatrix}\mathbf k
=-60\,\mathbf i-(-9)\,\mathbf j+76\,\mathbf k
=\begin{bmatrix}-60\\9\\76\end{bmatrix}

which makes

\left(-\dfrac34\mathbf v\right)\times\left(-\dfrac12\mathbf w\right)=\dfrac38\begin{bmatrix}-60\\9\\76\end{bmatrix}=\begin{bmatrix}-\frac{45}2\\\\\frac{27}8\\\\\frac{57}2\end{bmatrix}
4 0
3 years ago
Find three consecutive odd integers such that the sum of the least integer and the middle integer is 51 more than the greatest i
Shkiper50 [21]

Answer:

square root of 25 <square root of 51 <square root of 81

5 <7.14 <9

4 0
3 years ago
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