Answer:
{12,2}
Step-by-step explanation:
From the given graph it is clear that the initial point of the vector is (-5,0) and the terminal point (7,2).
If initial point of a vector is
and terminal point is
, then

Using this formula, we get



Using braces, we get

Therefore, the required vector is {12,2}.
Answer:
A
Step-by-step explanation:
All of the values are represented correctly on the histogram. It represents both the points and the frequencies in the correct way.
Answer:
<u>B) 25.12 cm</u>
Step-by-step explanation:
<u>Arc length</u>
- 2πr x 1/4
- 2 x 3.14 x 16/4
- 8 x 3.14
- <u>25.12 cm</u>
V = 1/3Bh
B = 1/2(b1 + b2)t
V = 1/3[1/2(b1 + b2)t] * h
h = 24
b1 = 13
b2 = 29
t = ?
V = 2856
Substitute:
2856 = 1/3[1/2(13 + 29)t](24)
2856 = 1/6(42)(24)t
2856 = 7(24)t
2856 = 168t
t = 2856/168 = 17 in height of the trapeziod
A = 1
b = -5
c = -4
x1 = 5.70
x2 = -0.70
<span>Therefore, the negative real number is -0.70.</span>