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Dafna11 [192]
3 years ago
9

Can someone help me please

Mathematics
1 answer:
Vika [28.1K]3 years ago
3 0

Answer:

15 - 17 = 0.013333 (1.3333%)

latte drop = 8.3%

gasoline = 9%

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According to an​ almanac, 60​% of adult smokers started smoking before turning 18 years old. ​(a) compute the mean and standard
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The given problem describes a binomial distribution with p = 60% = 0.6. Given that there are 400 trials, i.e. n = 400.

a.) The mean is given by:

\mu=np=400\times0.6=240

The standard deviation is given by:

\sigma=\sqrt{npq} \\  \\ =\sqrt{np(1-p)} \\  \\ =\sqrt{400(0.6)(0.4)} \\  \\ =\sqrt{96}=9.80


b.)  The mean means that in an experiment of 400 adult smokers, we expect on the average to get about 240 smokers who started smoking before turning 18 years.


c.) It would be unusual to observe <span>340 smokers who started smoking before turning 18 years old in a random sample of 400 adult​ smokers because 340 is far greater than the mean of the distribution.
340 is greater than 3 standard deviations from the mean of the distribution.</span>
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Which value is the furthest from 0 on the number line?
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Of all the students enrolled in the school of arts who responded, approximately what proportion responded that they play video g
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A square pyramid has a base with side lengths each measuring 40 inches. The pyramid is 21 inches tall, with a slant height of 29
Alchen [17]

Answer    

Find out the  what is the surface area of the pyramid .

To proof

Formula

Surface area of a square pyramid

= a^{2} + 2a \sqrt{\frac{a^{2}}{4} +h^{2}

Where a is the base edge and h be the height .

As given

A square pyramid has a base with side lengths each measuring 40 inches. The pyramid is 21 inches tall, with a slant height of 29 inches.

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Height =  21 inches    

Put values in the above formula

= 40^{2} + 2\times40\times\sqrt{\frac{40^{2}}{4} +21^{2}

solving

= 1600 + 80 \sqrt{\frac{1600}{4} + 441

= 1600 + 80\times\sqrt{841}

\sqrt{841} = 29

= 1600 + 80 × 29

= 3920 inches²

Therefore the surface area of the pyramid is 3,920 inches²

Hence proved

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