Real life example of a non-linear function

In the past, the average age of employees of a large corporation has been 40 years. Recently, the company has been hiring older

Viktor [21]

Answer:

$p_v =P(t_{(63)}>2.5)=0.0075$

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can conclude that the mean age is significantly higher than 45 years at 5% of significance.

Step-by-step explanation:

1) Data given and notation

$\bar X=45$ represent the mean height for the sample

$s=16$ represent the sample standard deviation for the sample

$n=64$ sample size

$\mu_o =40$ represent the value that we want to test

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean age is higher than 40 years, the system of hypothesis would be:

Null hypothesis: $\mu \leq 40$

Alternative hypothesis: $\mu > 40$

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{45-40}{\frac{16}{\sqrt{64}}}=2.5$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n-1=64-1=63$

Since is a one right tailed test the p value would be:

$p_v =P(t_{(63)}>2.5)=0.0075$

Conclusion

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can conclude that the mean age is significantly higher than 45 years at 5% of significance.

6 0

3 years ago

What is the value of 6/x + 2x2, when x = 3?

aliina [53]

Replace x = 3 into <span>6/x + 2x^2

</span>6/x + 2x^2

=6/3 + 2 (3)^2
= 2 + 2(9)
= 2 + 18
= 20

3 0

2 years ago

What is the mystery number? The greatest common factor of the mystery pair is 7. The least common multiple of the mystery pair i

xxMikexx [17]

The ANSWER to the mystery question is 50

5 0

3 years ago

Read 2 more answers

In a function if the vaule of a changes in response to the vaule of b then b is the

d1i1m1o1n [39]

<span>b is the independent variable ok</span>

5 0

3 years ago

. A salesman sold 300 bags of maize to a retailer at Kshs .2000 each .He was given a commission of 3%.The salesman allowed a dis

nalin [4]

Answer:

The discount allowed per bag is kshs 4

while the discount allowed on all the 300 bags is kshs 1,200

Step-by-step explanation:

Here, we are interested in calculating the discount allowed on the sales of the bag of maize.

From the question, we are told that the sales man allowed a discount of 0.2% on the maize sold.

Now, to find the amount of this, we proceed as follows;

What we simply need to do is to find 0.2% of the each of the price of the maize bags, and then we can proceed to find the total discount given on all maize bags sold.

The discount on each bag of maize would be;

0.2% of kshs 2000

That would be;

0.2/100 * 2,000 = 400/100 = kshs 4

Since there are 300 bags, the total amount of discount allowed is 300 * kshs 4 = kshs 1,200

8 0

3 years ago