The complete question in the attached figure
we know that
the triangle AOB is congruent with triangle AOC
because
AB=AC
OB=OC-----> the radius of the circle
<span>The OB side is common
</span>but
<span>there is no additional information that allows me to calculate the OBA angle to determine if it is a right angle
</span>
therefore
the answer is the option<span>
C. There is no indication that AB and AC are perpendicular to the radii at the points of intersection with the circle.</span>
<span>This intersection produces a line. However, if the angle of the plane is less than the cone's angle, then the intersection produces a point. If the angle of the plane is greater than the angle of the cone, then the intersection is two lines intersecting at the vertex. If the plane intersects at some point other than the vertex, then the intersection is a circle if the plane is perpendicular to the cone's axis. It is an ellipse when the plane's angle is less than the cone's angle. It's a parabola when the planes's angle equals the cone's angle.</span>
I believe the answer is C
The value of x is -2 and the value of y is -1.
Step-by-step explanation:
Step 1; The given equations are taken as
-3y -9x =21 or -9x -3y = 21, take this as equation 1
-18x +4y =32, take this as equation 2
Step 2; We multiply equation 1 with 2 and equation 2 with 1 so we can cancel out the variable x in both equations. By doing this we get
-18x -6y =42, take this as equation 3
-18x +4y =32, this is the same as equation 2
If we subtract 3 with 2, we cancel out the x variable and can calculate the value of y.
10y = -10 , y = -10/10 = -1
Step 3; Substituting this value of y in any of the previous equations we will get x's value. Here this value of y is substituted in equation 2.
-18x +4(-1) =32, -18x -4 = 32 , -18x = 36, x=-2.
So we have x = -2 and y = -1.