In a board game, students draw a number do not replace it, and then draw a second number. Determine the probability of each even
1 answer:
The figure depicting the board game is attached below.
Answer:
Step-by-step explanation:
Kindly note that selections done without replacement.
Count of numbers on the board game = 8
Count of odd numbers = (1, 9, 1) = 3
Count of digit 6 = 3
Probability = required outcome / Total possible outcomes
P(picking an odd number) = 3 / 8
Without replacement
Numbers left on board game = 8 - 1 = 7
P(picking a 6) = 3 / 7
Hence,
P(picking an odd number then, a 6) = 3/8 * 3/7 = 9 / 56
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Answer:
Solution : 8i
Step-by-step explanation:
We can use the trivial identities cos(π / 2) = 0, and sin(π / 2) = 1 to solve this problem. Let's substitute,
=
And of course 1i = i, so we have the expression 8(0 + i ). Distributing the " 8, " 8( 0 ) = 0, and 8(i) = 8i, making the fourth answer the correct solution.