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elena-14-01-66 [18.8K]
3 years ago
13

In a board game, students draw a number do not replace it, and then draw a second number. Determine the probability of each even

t occurring. Drawing an odd number then drawing a 6? dependent events. PLEASE HELP ME
Mathematics
1 answer:
murzikaleks [220]3 years ago
7 0

The figure depicting the board game is attached below.

Answer:

Step-by-step explanation:

Kindly note that selections done without replacement.

Count of numbers on the board game = 8

Count of odd numbers = (1, 9, 1) = 3

Count of digit 6 = 3

Probability = required outcome / Total possible outcomes

P(picking an odd number) = 3 / 8

Without replacement

Numbers left on board game = 8 - 1 = 7

P(picking a 6) = 3 / 7

Hence,

P(picking an odd number then, a 6) = 3/8 * 3/7 = 9 / 56

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Answer:

Step-by-step explanation:

1. You can use the intercepts to graph the line. The graph of 2x + 3y = 12      crosses the x-axis at (6, 0), so its x-intercept is 6. The graph of 2x + 3y = 12  crosses the y-axis at (0, 4), so its y-intercept is 4.

2. Point-Slope Form: y - y1 = m(x - x1)

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2 years ago
Can you help me please?
9966 [12]
First, change the two mixed numbers in the expression into an improper fraction: 25/6 + 5/3.
Then, find the Lowest Common Denominator of both fractions, which is 6, and set both denominators equal to that.  Remember, whatever you do on one side you must do to the other: 25/6 + 10/6
Add the two together: 25/6 +10/6 = 35/6.
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3 years ago
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Answer:

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