In a board game, students draw a number do not replace it, and then draw a second number. Determine the probability of each even
1 answer:
The figure depicting the board game is attached below.
Answer:
Step-by-step explanation:
Kindly note that selections done without replacement.
Count of numbers on the board game = 8
Count of odd numbers = (1, 9, 1) = 3
Count of digit 6 = 3
Probability = required outcome / Total possible outcomes
P(picking an odd number) = 3 / 8
Without replacement
Numbers left on board game = 8 - 1 = 7
P(picking a 6) = 3 / 7
Hence,
P(picking an odd number then, a 6) = 3/8 * 3/7 = 9 / 56
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