A = 57
45 + 12 = 57
57 - (-12) = 45
Plug in numbers in for x.
If you plug in 0 then you get 1. 1/0 is undefined
If you plug in 1 then you get 6. 6/1 is 6
If you plug in 2 then you get 11. 11/2 is 5.5
If you plug in 3 then you get 16. 16/3 is 5.3 repeating
If you plug in 4 then you get 21. 21/4 is 5.25
If you plug in 5 then you get 26. 26/5 is 5.2
It would only be proportional if you got the same answer after dividing each time.
2/5 in 1/12 of an hour
x in 1 hour
So multiply 12 to both fractions
2/5 x 12 in 1/12 x 12 of an hour
We get now:
24/5 in 1 hour
or:
4 4/5 in 1 hour
Answer:
x= 3 hope it helps thanks
Answer:

Step-by-step explanation:
We are given that linear differential equation

Auxillary equation


C.F=
P.I=
P.I=
P.I=
and
where D square is replace by - a square
P.I=
Hence, the general solution
G.S=C.F+P.I
