There are two ways to do this
Method 1:
Find (f-g)(x) first
(f-g)(x) = f(x) - g(x)
(f-g)(x) = (5x^2+3) - (-2x+4)
(f-g)(x) = 5x^2+3+2x-4
(f-g)(x) = 5x^2+2x-1
Then plug in x = -3
(f-g)(-3) = 5(-3)^2+2(-3)-1
(f-g)(-3) = 5(9)+2(-3)-1
(f-g)(-3) = 45-6-1
(f-g)(-3) = 39-1
(f-g)(-3) = 38
-----------------------------------------
Method 2:
Find f(-3)
f(x) = 5x^2+3
f(-3) = 5(-3)^2+3
f(-3) = 5(9)+3
f(-3) = 45+3
f(-3) = 48
Find g(-3)
g(x) = -2x+4
g(-3) = -2(-3)+4
g(-3) = 6+4
g(-3) = 10
Subtract the two results
(f-g)(-3) = f(-3) - g(-3)
(f-g)(-3) = 48 - 10
(f-g)(-3) = 38
-----------------------------------------
Whichever method you pick, the answer is: 38
Answer:
Normally Distributed.
Explanation:
After plugging all those numbers into a calculator you can see that the graph isn't left skewed, making both "left skewed" and "all of the above" <em>not an answer.</em> "correlated with a second set of data" is also <em>wrong</em> since there was no second set of data given. That leaves you between "uniformly distributed" and "normally distributed" This graph doesn't show a uniformly distributed graph, which leaves you with the final answer, normally distributed.
APEX
3 5/6
I think, I haven’t done this in a long time.
Answer:
1/64
Step-by-step explanation:
4x4^3/4^7
4^-3
1/4^3
<u>1/64</u>
<u />
<u />
Answer: 
Step-by-step explanation:
Given
Rectangle has an area of 
Suppose rectangle length and width are 
and 
If each side is increased by 
Area becomes 
We can write
Substitute the value of width from (ii) in equation (i)
Width corresponding to these lengths
Therfore, we can write the length of the longer side is
