S=d/t
for liam
4=.25/t
t=.25/4
t=0.0625hours
for harper
t=0.25/4.5=0.055hours
msg me if it helps
Answer:
A sample of 16577 is required.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the z-score that has a p-value of
.
The margin of error is of:

99% confidence level
So
, z is the value of Z that has a p-value of
, so
.
She wants to estimate the proportion using a 99% confidence interval with a margin of error of at most 0.01. How large a sample size would be required?
We have no estimation for the proportion, and thus we use
, which is when the largest sample size will be needed.
The sample size is n for which M = 0.01. So






Rounding up:
A sample of 16577 is required.
(x^m) times (x^n)=x^(m+n)
(1/8)^5 times (1/8)^3=(1/8)^(5+3)=(1/8)^8=1/(8^8)