PLEASE HELP!!!!!!!!!!!!!!!!!!!!!

sam wants to cut a 57'' piece of wire into pieces 3/4 long. how many pieces how many pieces will he be able to cut

NeTakaya

This is a division problem involving fractions.
57 / (3/4)
57 * (4/3) =
128/3 = 76 pieces of wire

8 0

3 years ago

Find the measure of the central angle with an arc length equaling 29.21 and a circumference = 40.44

Dima020 [189]

measure of central angle is 4.607 radians with an arc length equaling 29.21 and a circumference = 40.44

Step-by-step explanation:

Arc length = 29.21

Circumference = 40.44

Central angle = ?

The formula used to find central angle is:

$s=r\theta$

where s = arc length, r= radius and Ф=central angle.

We need to find radius from circumference

$c=2\pi r\\r=\frac{c}{2\pi } \\Putting\,\,values:\\r=\frac{40.44}{2*3.14}\\r=6.43$

So, radius = 6.34

Now, finding central angle:

$s=r\theta\\29.21=6.34\,\,\theta\\\theta=\frac{29.21}{6.34}\\\theta=4.607\,\,radians$

So, measure of central angle is 4.607 radians with an arc length equaling 29.21 and a circumference = 40.44

Keywords: Central angle of circle

Learn more about Central angle of circle at:

#learnwithBrainly

5 0

3 years ago

A sample of 250 people resulted in a confidence interval estimate for the proportion of people who believe that the federal gove

bagirrra123 [75]

Answer: Approximately 79 Percent

Step-by-step explanation:

The confidence level used in this estimation is approximately 79 percent.

3 0

3 years ago

maria took 7 hours to read a 259-page book and juanita took 5 hours to read a 175-page book. who read more pages per hour? expla

Temka [501]

Answer: Maria reads more pages per hour

Step-by-step explanation:

Maria - 37 pages per hour

259 = pages read

7 = hours

259/7

37

Juanita - 35 pages per hour

175 = pages read

5 = hours

175/5

35

3 0

3 years ago

Consider a particle moving along the x-axis where x(t) is the position of the particle at time t, x' (t) is its velocity, and x'

vodka [1.7K]

Answer:

a) $v(t) =x'(t) = \frac{dx}{dt} = 3t^2 -12t +9$

$a(t) = x''(t) = v'(t) =6t-12$

b) $0$

c) $a(t) = x''(t) = v'(t) =6t-12$

When the acceleration is 0 we have:

$6t-12=0, t =2$

And if we replace t=2 in the velocity function we got:

$v(t) = 3(2)^2 -12(2) +9=-3$

Step-by-step explanation:

For this case we have defined the following function for the position of the particle:

$x(t) = t^3 -6t^2 +9t -5 , 0\leq t\leq 10$

Part a

From definition we know that the velocity is the first derivate of the position respect to time and the accelerations is the second derivate of the position respect the time so we have this:

$v(t) =x'(t) = \frac{dx}{dt} = 3t^2 -12t +9$

$a(t) = x''(t) = v'(t) =6t-12$

Part b

For this case we need to analyze the velocity function and where is increasing. The velocity function is given by:

$v(t) = 3t^2 -12t +9$

We can factorize this function as $v(t)= 3 (t^2- 4t +3)=3(t-3)(t-1)$

So from this we can see that we have two values where the function is equal to 0, t=3 and t=1, since our original interval is $0\leq t\leq 10$ we need to analyze the following intervals:

$0< t$

For this case if we select two values let's say 0.25 and 0.5 we see that

$v(0.25) =6.1875, v(0.5)=3.75$

And we see that for $a=0.5 >0.25=b$ we have that f(b)>f(a) so then the function is decreasing on this case.

$1$

We have a minimum at t=2 since at this value w ehave the vertex of the parabola :

$v_x =-\frac{b}{2a}= -\frac{-12}{2*3}= -2$

And at t=-2 v(2) = -3 that represent the minimum for this function, we see that if we select two values let's say 1.5 and 1.75

v(1.75) =-2.8125< -2.25= v(1.5) so then the function sis decreasing on the interval 1<t<2

$2$

We see that the function would be increasing.

$3$

For this interval we will see that for any two points a,b with $a>b$ we have $f(a)>f(b)$ for example let's say a=3 and b =4

$f(a=3) =0 , f(b=4) =9 , f(b)>f(a)$

The particle is moving to the right then the velocity is positive so then the answer for this case is: $0$

Part c

$a(t) = x''(t) = v'(t) =6t-12$

When the acceleration is 0 we have:

$6t-12=0, t =2$

And if we replace t=2 in the velocity function we got:

$v(t) = 3(2)^2 -12(2) +9=-3$

5 0

3 years ago