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ryzh [129]
3 years ago
15

PLEASE HELP!!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
Shalnov [3]3 years ago
8 0

Answer:

D i think sorry if wrong

Step-by-step explanation:

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Find f(-2) for f(x) = 2(4)x . will give brainliest for correct answer ​
Serhud [2]

Answer:

D

Step-by-step explanation:

This questions asks use to find what f(x) or y is, when x is equal to -2.

So, substitute -2 in for x in the equation.

f(x)=2(4)^x

f(-2)=2(4)^-2

Evaluate the exponent. Negative exponents follow this rule:

b^-x= 1/b^x

We have 4^-2. This will become 1/4^2 or 1/16

f(-2)=2(1/16)

Multiply

f(-2)=2/16

This fraction can be simplified. Both the numerator (top number) and denominator (bottom number) can be divided by 2.

f(-2)=2/2 / 16/2

f(-2)= 1/8

The correct choice is D. 1/8

8 0
3 years ago
3. The photo below is being enlarged to form
Umnica [9.8K]

Answer:

Not enough information

Step-by-step explanation:

Add the photo next time

4 0
3 years ago
Atreya runs 5 1/4 miles in 3/4 of an hour. If Atreyu continues at this rate, how far will he run in an hour?
kogti [31]

Answer: 63/16 = 3 1/16 or 7 if your divide it

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
Decide if 6x + 2 = 2 + 6x has no solution, one solution, or infinitely many solutions
Elanso [62]

Answer:

HI!

Step-by-step explanation:

BYE!

Sorry :(

3 0
3 years ago
Carla wants the total weight of the bags to be four pounds. If she can only pick one more bag, which bag weight should she pick?
pychu [463]

Answer:

1/8

Step-by-step explanation:

To find which bag weight Carla needs, the first step is to find the total weight of the bags shown in the line plot.

There are three -pound bags.

There are six -pound bags.

There are four -pound bags.

Multiply the weight and number of each bag to find the total weight of each different weight bag.

Now, add the three totals.

Finally, subtract the total weight from four pounds in order to find which weight Carla needs.

So, Carla should pick one -pound bag of candy to total four pounds.

4 0
3 years ago
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