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zepelin [54]
3 years ago
7

The speed that a tsunami can travel is modeled by the equation s = 356 StartRoot d EndRoot , where S is the speed in kilometers

per hour and d is the average depth of the water in kilometers. What is the approximate depth of water for a tsunami traveling at 200 kilometers per hour?
Mathematics
1 answer:
zalisa [80]3 years ago
6 0

Answer:

0.32km

Step-by-step explanation:

The speed that a tsunami can travel is modeled by the equation s = 356 StartRoot d EndRoot , where S is the speed in kilometers per hour and d is the average depth of the water in kilometers.

This is written mathematically as:

S = 356√d

What is the approximate depth of water for a tsunami traveling at 200 kilometers per hour?

S = 200km/hr

Hence:

200km/hr = 356√d

Divide both sides by 356

200/356 = 356√d/356

√d = 200/356

Square both sides

(√d)² = (200/356)²

d =(0.5617977528)²

d = 0.3156167151km

Approximately = 0.32km

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What is the value of the sum of all the terms of the geometric series 300, 60, 12, …?
ruslelena [56]
<h3>Answer:   375</h3>

=========================================

Work Shown:

a = 300 = first term

r = 60/300 = 0.2 = common ratio

We multiply each term by 0.2, aka 1/5, to get the next term.

Since -1 < r < 1 is true, we can use the infinite geometric sum formula below

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As a sort of "check", we can add up partial sums like so

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and so on. The idea is that each time we add on a new term, we should be getting closer and closer to 375. I put "check" in quotation marks because it's probably not the rigorous of checks possible. But it may give a good idea of what's going on.

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Side note: If the common ratio r was either r < -1 or r > 1, then the terms we add on would get larger and larger. This would mean we don't approach a single finite value with the infinite sum.

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3 years ago
How to find the equation?
bixtya [17]

Answer:

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then solve for b

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