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zepelin [54]
3 years ago
7

The speed that a tsunami can travel is modeled by the equation s = 356 StartRoot d EndRoot , where S is the speed in kilometers

per hour and d is the average depth of the water in kilometers. What is the approximate depth of water for a tsunami traveling at 200 kilometers per hour?
Mathematics
1 answer:
zalisa [80]3 years ago
6 0

Answer:

0.32km

Step-by-step explanation:

The speed that a tsunami can travel is modeled by the equation s = 356 StartRoot d EndRoot , where S is the speed in kilometers per hour and d is the average depth of the water in kilometers.

This is written mathematically as:

S = 356√d

What is the approximate depth of water for a tsunami traveling at 200 kilometers per hour?

S = 200km/hr

Hence:

200km/hr = 356√d

Divide both sides by 356

200/356 = 356√d/356

√d = 200/356

Square both sides

(√d)² = (200/356)²

d =(0.5617977528)²

d = 0.3156167151km

Approximately = 0.32km

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Step-by-step explanation:

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an artist painted a 6 foot tall painting, then decide to also create a smaller version. if she uses a scale of 4 inches=1.5 feet
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A carpenter is building a rectangular room with a fixed perimeter of 300 ft. what dimensions would yield the maximum​ area?
Inessa05 [86]

Perimeter = 2(Length) + 2(Width)

300 = 2L + 2W → 150 = L + W → 150 - L = W

Area = Length · Width

A_{max} = L(150 - L) → A_{max} = 150L - L²

There are 2 different methods for solving (depending on which math course you are taking).

<u>Calculus</u>: find the derivative, set it equal to zero, and solve for L.

A_{max} = 150L - L² → 0 = 150 - 2L → 2L = 150 → L = 75

<u>Algebra</u>: find the vertex.

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Once you solve for L, plug it into the Perimeter equation to solve for W:

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