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shtirl [24]
3 years ago
9

If the ratio of areas of two similar polygons is 25:49, what is the ratio of the corresponding side lengths

Mathematics
1 answer:
mihalych1998 [28]3 years ago
6 0
\bf \qquad \qquad \textit{ratio relations}
\\\\
\begin{array}{ccccllll}
&Sides&Area&Volume\\
&-----&-----&-----\\
\cfrac{\textit{similar shape}}{\textit{similar shape}}&\cfrac{s}{s}&\cfrac{s^2}{s^2}&\cfrac{s^3}{s^3}
\end{array} \\\\
-----------------------------\\\\

\bf \cfrac{\textit{similar shape}}{\textit{similar shape}}\qquad \cfrac{s}{s}=\cfrac{\sqrt{s^2}}{\sqrt{s^2}}=\cfrac{\sqrt[3]{s^3}}{\sqrt[3]{s^3}}\\\\
-------------------------------\\\\
\stackrel{\textit{ratio of sides}}{\cfrac{s}{s}}=\stackrel{\textit{ratio of the areas}}{\cfrac{\sqrt{s^2}}{\sqrt{s^2}}}\implies \cfrac{s}{s}=\cfrac{\sqrt{25}}{\sqrt{49}}\implies \cfrac{s}{s}=\cfrac{5}{7}
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boyakko [2]

Answer:

  (7√6)/2

Step-by-step explanation:

The side ratios in these special triangles are ...

  30°-60°-90° triangle: 1 : √3 : 2

  45°-45°-90° triangle: 1 : 1 : √2

This tells you the length of the horizontal line is 7√3, and the value of x is ...

  (7√3)/√2 = (7√6)/2

_____

<em>Additional comment</em>

Call the length of the horizontal line "y". Then the given ratios tell you ...

  7 : y = 1 : √3   ⇒   y/7 = √3/1   ⇒   y = 7√3

and

  x : y = 1 : √2   ⇒   x/y = 1/√2   ⇒   x = y/√2

When we rationalize the denominator, we get ...

  x = (y√2)/2 = ((7√3)√2)/2 = (7√6)/2

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Step-by-step explanation:

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