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3 years ago

If the ratio of areas of two similar polygons is 25:49, what is the ratio of the corresponding side lengths

1 answer:

mihalych1998 [28]3 years ago

6 0

$\bf \qquad \qquad \textit{ratio relations}
\\\\
\begin{array}{ccccllll}
&Sides&Area&Volume\\
&-----&-----&-----\\
\cfrac{\textit{similar shape}}{\textit{similar shape}}&\cfrac{s}{s}&\cfrac{s^2}{s^2}&\cfrac{s^3}{s^3}
\end{array} \\\\
-----------------------------\\\\$

$\bf \cfrac{\textit{similar shape}}{\textit{similar shape}}\qquad \cfrac{s}{s}=\cfrac{\sqrt{s^2}}{\sqrt{s^2}}=\cfrac{\sqrt[3]{s^3}}{\sqrt[3]{s^3}}\\\\
-------------------------------\\\\
\stackrel{\textit{ratio of sides}}{\cfrac{s}{s}}=\stackrel{\textit{ratio of the areas}}{\cfrac{\sqrt{s^2}}{\sqrt{s^2}}}\implies \cfrac{s}{s}=\cfrac{\sqrt{25}}{\sqrt{49}}\implies \cfrac{s}{s}=\cfrac{5}{7}$

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3 years ago

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Vadim26 [7]

Answer:

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Step-by-step explanation:

The x intercepts are the values of x when y = 0 ie the roots of the equation
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The line of symmetry is the vertical line corresponding to the vertex x value so line of symmetry is at x = -0.5

The graph of the quadratic function shows these values

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2 years ago