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KatRina [158]
3 years ago
5

Dito isulat ang solusyon.​

Mathematics
1 answer:
IgorC [24]3 years ago
5 0

Answer:

nasan ang tanong

Step-by-step explanation:

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What is 4 2/7 as an improper fraction?
mojhsa [17]
The answer should be B
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4 years ago
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Simplify the expression shown below:<br> log(10^6 X^2), where x &gt; 0
Paul [167]

Answer:

2^6 Times 5^6x^6

Step-by-step explanation:

8 0
3 years ago
Y = 2(x - 8)(x+2)
ss7ja [257]

Answer:

Step-by-step explanation:

y=2(x-8)(x+2)

The x intercepts occur when y=0, so when x=8 and -2

The vertex is where the equation is at a minimum/maximum in this case (x,y)=(3,-50)

The axis of symmetry occurs between the two roots, 8 and -2 which x=3

The y intercept is the value of y when x=0, in this case (0, -32)

5 0
3 years ago
Suppose that the members of a student governance committee will be selected from the 40 members of the student senate. There are
Len [333]

Answer:

The total number of ways to form a student governance committee is 1,211,760.

Step-by-step explanation:

The students senate consists of a total of 40 students.

The students are either Sophomores or Juniors or Seniors.

The number of students in each of these categories are as follows:

Sophomores = 18

Juniors = 12

Seniors = 10

A governance committee have to be selected from the students senate.

The committee have to made up of 2 sophomores, 2 juniors and 3 seniors.

Combinations can be used to select 2 sophomores from 18, 2 juniors from 12 and 3 seniors from 10.

Combinations is a mathematical technique used to determine the number of ways to select <em>k</em> items from <em>n</em> distinct items.

The formula is:

{n\choose k}=\frac{n!}{k!(n-k)!}

(1)

Compute the number of ways to select 2 sophomores from 18 as follows:

{n\choose k}=\frac{n!}{k!(n-k)!}

{18\choose 2}=\frac{18!}{2!(18-2)!}=\frac{18\times 17\times 16!}{2\times 16!}=153

Thus, there are 153 ways to select 2 sophomores from 18.

(2)

Compute the number of ways to select 2 juniors from 12 as follows:

{n\choose k}=\frac{n!}{k!(n-k)!}

{12\choose 2}=\frac{12!}{2!(12-2)!}=\frac{12\times 11\times 10!}{2\times 10!}=66

Thus, there are 66 ways to select 2 juniors from 12.

(3)

Compute the number of ways to select 3 seniors from 10 as follows:

{n\choose k}=\frac{n!}{k!(n-k)!}

{10\choose 3}=\frac{10!}{3!(10-3)!}=\frac{10\times 9\times 8\times 7!}{2\times 3\times 7!}=120

Thus, there are 120 ways to select 3 seniors from 10.

The total number of ways to form a student governance committee that must have 2 sophomores, 2 juniors and 3 seniors is:

Total number of ways = {18\choose 2}\times {12\choose 2}\times {10\choose 3}

                                    =153\times 66\times 120\\=1211760

Thus, the total number of ways to form a student governance committee is 1,211,760.

7 0
3 years ago
McKayla hikes 8 miles on Monday. On Tuesday she
Lady_Fox [76]

Answer:

10.4 miles

Step-by-step explanation:

convert 30% to a decimal 0.3

Then multiply 8×0.3=2.4

Now you have to add 2.4 to 8 because it is 39% more

4 0
3 years ago
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