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Ipatiy [6.2K]
3 years ago
6

A compact car gets 36 miles of gas how many miles can the car travel on 6 3/4 of gas

Mathematics
2 answers:
mel-nik [20]3 years ago
7 0

Answer:

243

Step-by-step explanation:

Lady_Fox [76]3 years ago
3 0
6+(3•4)=1273737828274&292937489292
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which equation, written in standard form correctly represents this scenario and indicates what the variables represent?
pishuonlain [190]

The answer is the third option.

The explanation is shown below:

1. You must keep on mind the information given in the exercise:

- She bough 3 pounds of coffee.

- She bought 2 pounds of chocolate.

- She spent a total of $24.

2. Therefore, you can call the price per pound of coffee x and the price per pound of chocolate y.

3. When you multiply 3 pounds by the price per pound of coffee, you obtain the amount of money she spent for 3 pounds. When you multiply 2 pounds by the price per pound of chocolate, you obtain the amount of money she spent for 2 pounds. If you add both amounts, you obtain the total spent, which was $24.

4. Therefore, you can express this as following:

3x+2y=24

5 0
3 years ago
Determine the equation of the line that passes through the given points. (If you have a graphing calculator, you can use the tab
siniylev [52]

Answer:

y = -2x

Step-by-step explanation:

It passes through -5, 10 and 5, -10

gradient = Δy/Δx

gradient = -10 - 10 / 5 -- 5

gradient = -20 / 10

gradient = -2

let's use -5, 10 for y = mx + b

10 = -2(-5) + b

10 = 10 + b

b = 10 - 10

b = 0.

the equation of the line is just y = -2x

6 0
2 years ago
(-w^3 + 8w^2 – 3w) + (-8w^2 + w + 3) =
kherson [118]
The expression simplified is -w^3-2w+3

I hope this helped
4 0
3 years ago
HEY YA'LL 30 PTS FOR 1 PROBLEM!<br> Given: m∠EYL=1/3 the measure of arc EHL<br> Find: m∠EYL.
GarryVolchara [31]

Answer:

45

Step-by-step explanation:

Two tangents drawn to a circle from an outside point form arcs and an angle, and this formula shows the relation between the angle and the two arcs.

m<EYL = (1/2)(m(arc)EVL - m(arc)EHL)      Eq. 1

The sum of the angle measures of the two arcs is the angle measure of the entire circle, 360 deg.

m(arc)EVL + m(arc)EHL = 360

m(arc)EVL = 360 - m(arc)EHL      Eq. 2

We are given this:

m<EYL = (1/3)m(arc)EHL       Eq. 3

Substitute equations 2 and 3 into equation 1.

(1/3)m(arc)EHL = (1/2)[(360 - m(arc)EHL) - m(arc)EHL]

Now we have a single unknown, m(arc)EHL, so we solve for it.

2m(arc)EHL = 3[360 - m(arc)EHL - m(arc)EHL]

2m(arc)EHL = 1080 - 6m(arc)EHL

8m(arc)EHL = 1080

m(arc)EHL = 135

Substitute the arc measure just found in Equation 3.

m<EYL = (1/3)m(arc)EHL

m<EYL = (1/3)(135)

m<EYL = 45

5 0
3 years ago
Factor the expression <br> 5x^2 -22x -15
Murljashka [212]
5x^2-22x-15=5x^2\underbrace{-25x+3x}_{-22x}-15\\\\=(5x^2-25x)+(3x-15)=5x(x-5)+3(x-5)\\\\=\boxed{(x-5)(5x+3)}

3 0
3 years ago
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