A car dealership collected data on the cars for sale. According to the data

-2v3 + v75

Lena [83]

Answer:

a) $3\sqrt{3}$

Step-by-step explanation:

Step(i):-

Given - 2 √3 + √75

we know that 25 × 3 = 75

- 2 √3 + √75

= -2 √3 + $\sqrt{25 X 3}$

By using

$\sqrt{ab} = \sqrt{a} \sqrt{b}$

= $-2\sqrt{3} + \sqrt{25} X \sqrt{3}$

= $-2\sqrt{3} + 5 \sqrt{3}$

= $(-2 + 5 ) \sqrt{3}$

= $3\sqrt{3}$

3 0

3 years ago

A gold mine is projected to produce $52,000 during its first year of operation, $50,000 the second year, $48,000 the third year,

marshall27 [118]

Answer:

its present worth is nearest to 483,566

Option d) 483,566 is the correct answer

Step-by-step explanation:

Given that;

gold mine is projected to produce $52,000 during its first year

produce $50,000 the second year

produce $48,000 the third year

the mine is expected to produce for 20yrs; i.e n = 20

annual interest rate = 4% = 0.04%

now let P represent the present worth

we determine the present worth ;

Present worth ⇒ Cashflow(Uniform series present worth) - (2000)(uniform gradient present worth)

⇒Cashflow(P | A,i%,n) - (2000)(P | G,i%,n)

= 52000[ ((1+i)ⁿ - 1) / (i(1+i)ⁿ) ] - (2000)[ {((1+i)ⁿ - 1) / (i²(1+i)ⁿ))} - (n/i(1 + i)ⁿ) ]

= 52000[ ((1+0.04)²⁰ - 1) / (0.04(1+0.04)²⁰) ] - (2000)[ {((1+0.04)20 - 1) / ((0.04)²(1+0.04)²⁰))} - (20/0.04(1 + 0.04)²⁰) ]

= 52000[ ((1.04)²⁰ - 1) / (0.04(1.04)²⁰) ] - (2000)[ {((1.04)²⁰ - 1) / ((0.04)²(1.04)²⁰))} - (20/0.04(1.04)²⁰) ]

= 52000[ ((2.191123 - 1) / (0.04(2.191123) ] - (2000)[ {((2.191123 - 1) / ((0.0016)(2.191123))} - (20/0.04(2.191123) ]

= 52000(1.191123/0.08764) - (2000){( 1.191123/0.003506) - (20/0.87645)}

= 52000(13.59033) - (2000)(339.7582 - 228.1935)

= 52000(13.59033) - (2000)(111.5647)

= 706695.6 - 223129.4

= 483,566.2 ≈ 483,566

Therefore its present worth is nearest to 483,566

Option d) 483,566 is the correct answer

4 0

3 years ago

Help pls and thank uu

Sergio039 [100]

Answer:

f(- 4) = - 4

Step-by-step explanation:

f(- 4) with x = - 4 gives f(- 4) = - 4

5 0

3 years ago

Brennan purchased an almond tart costing $18.56. He gave the cashier $19.55. How much change did the cashier give back to Brenna

11111nata11111 [884]

Answer:

0.99.

Step-by-step explanation:

7 0

3 years ago

Kelly runs a restaurant that sells two kinds of desserts. Kelly knows the restaurant must make at least 25 dozen and at most 45

MissTica

Answer:

(c, m) = (45, 10)

Step-by-step explanation:

A dozen White Chocolate Blizzards generate more income and take less flour than a dozen Mint Breezes, so production of those should clearly be maximized. Making 45 dozen Blizzards does not use all the flour, so the remaining flour can be used to make Breezes.

Maximum Blizzards that can be made: 45 dz. Flour used: 45×5 oz = 225 oz.

The remaining flour is ...

315 oz -225 oz = 90 oz

This is enough for (90 oz)/(9 oz/dz) = 10 dozen Mint Breezes. This is in the required range of 2 to 15 dozen.

Kelly should make 45 dozen White Chocolate Blizzards and 10 dozen Mint Breezes: (c, m) = (45, 10).

__

In the attached graph, we have reversed the applicable inequalities so the feasible region shows up white, instead of shaded with 5 different colors. The objective function is the green line, shown at the point that maximizes income. (c, m) ⇔ (x, y)

8 0

3 years ago