Using ƒ(x) = 3x − 3 and g(x) = -x, find g(ƒ(x)) a. 3x+3 b. 3-3x c.-3-3x d. 2x-3

Mathematics

1 answer:

Tresset [83]3 years ago

8 0

<h3>Answer: Choice B. 3 - 3x</h3>

Work Shown:

$g(x) = -x\\\\g(f(x)) = -f(x)\\\\g(f(x)) = -(3x-3)\\\\g(f(x)) = -3x+3\\\\g(f(x)) = \boldsymbol{3-3x}\\\\$

Explanation: We start with the outer function g(x). In the second step, we replace every copy of x with f(x). From there we plug in f(x) = 3x-3 and simplify using the distribution rule.

The notation $g(f(x))$ is the same as writing $(g \circ f)(x)$

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3. A kite is aloft at the end of a 1500 foot string. The string make an angle of 43° with the

sineoko [7]

Answer:

$h= 1500\,*\,sin(43^o)$

Step-by-step explanation:

Notice that there is a right angle triangle formed with sides as follows:

hypotenuse is the actual 1500 ft string. The acute angle 43 degrees is opposite to the segment that represents the height of the kite from the ground. Therefore, the trigonometric ratio that we can use to find that opposite side to the given angle, is the sine function as shown below:

$sin(43^o) = \frac{opposite}{hypotenuse} \\sin(43^o) = \frac{opposite}{1500}\\opposite = 1500\,*\,sin(43^o)\\h= 1500\,*\,sin(43^o)$