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Oksanka [162]
3 years ago
8

Using ƒ(x) = 3x − 3 and g(x) = -x, find g(ƒ(x)) a. 3x+3 b. 3-3x c.-3-3x d. 2x-3

Mathematics
1 answer:
Tresset [83]3 years ago
8 0
<h3>Answer:  Choice B.  3 - 3x</h3>

Work Shown:

g(x) = -x\\\\g(f(x)) = -f(x)\\\\g(f(x)) = -(3x-3)\\\\g(f(x)) = -3x+3\\\\g(f(x)) = \boldsymbol{3-3x}\\\\

Explanation: We start with the outer function g(x). In the second step, we replace every copy of x with f(x). From there we plug in f(x) = 3x-3 and simplify using the distribution rule.

The notation g(f(x)) is the same as writing (g \circ f)(x)

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Help it’s for my babies brother hw
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Solve for x when <img src="https://tex.z-dn.net/?f=x%5E%7Byz%7D%20%3Dy%5E%7B2%7D" id="TexFormula1" title="x^{yz} =y^{2}" alt="x^
Assoli18 [71]

The value of x in x^yz = y^2 is x = \sqrt[yz]{y^2}

<h3>How to solve for x?</h3>

The equation is given as:

x^yz = y^2

Rewrite the equation properly as follows

x^{yz} = y^2

Take the yz root of both sides

\sqrt[yz]{x^{yz}} = \sqrt[yz]{y^2}

Apply the law of indices

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Divide yz by yz

x = \sqrt[yz]{y^2}

Hence, the value of x in x^yz = y^2 is x = \sqrt[yz]{y^2}

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brainly.com/question/2972832

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