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inna [77]
3 years ago
10

3. the smallest number by which 168 must be multipled to get the perfect square number. ICA) 3 1(B)2 (c) 4 (o)5​

Mathematics
1 answer:
kaheart [24]3 years ago
5 0

Answer:

42

Step-by-step explanation:

168 factors into

2•2•2•3•7

two of the 2's make a perfect square

(2•2)•2•3•7

   2²•2•3•7

as none of the product of the remaining factors makes a perfect square

2•3 = 6,  2•7 = 14,  3•7 = 21

we need to multiply the remaining factors together to find another perfect square

   2²•(2•3•7)²

2•3•7 = 42

42(168) = 7056 = 84²

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PLEASE HELP ME OUT WITH MATH!
Helen [10]

Answer:

C

Step-by-step explanation:

If you multiply it out it looks like

7/1 times 1/8

multiply across (7 times 1 / 1 times 8)

gives you 7/8

7 0
2 years ago
Read 2 more answers
11. The probability that a dessert sold at a certain cafe contains chocolate is 75%. The probability that a dessert containing c
raketka [301]
probability that a dessert sold at a certain cafe contains chocolate is 86%.

The probability that a dessert containing chocolate also contains nuts is 30%.

Find the probability that a dessert chosen at random contains nuts given that it contains chocolate

P(nuts given chocolate) = .30/.86 = .349 or 34
6 0
3 years ago
A health food company packs almond butter in jars. Some jars hold 250 g. Other jars hold 500 g. On Tuesday, the company packed 1
MArishka [77]
Let the number of 250g=0.25  kg jars be x and that of 500g=0.5 kg jams be y;
therefore:
total number of jars ws
x+y=511
x=511-y..........i

total mount kgs was:
0.25x+0.5y=186.5....ii
substituting i in ii
0.25(511-y)+0.5y=186.5
127.75-0.25y+0.5y=186.5
solving for y we get:
0.25y=186.5-127.75
0.25y=58.75
y=58.75/0.25
y=235 jars
and 
x=511-x
=511-235
=276
hence we conclude that there was 235 jars with 0.5 kg almond and 276 jars with 0.25 kg almonds
5 0
3 years ago
Read 2 more answers
Use the points in the diagram to name the figure.<br><br> Answer choices attached below.
Elena-2011 [213]
It's the last answer DC. DC is a segment so there would be a line above it.
6 0
3 years ago
Point DD is located at (3,-3)(3,−3) on the coordinate plane. Point DD is reflected over the xx-axis to create point D'D ′ . What
stepan [7]

If the point D is located at (3,-3) on the coordinate plane and the point D is reflected over the x-axis to create point D', then the ordered pair describes  the location of D' is (3,3)

The coordinates of the point = (3,-3)

Then the point D is reflected over the x-axis to create the point D'

The point the point is reflected over the x axis, the coordinates of the points will become

A(x,y) = A'(x,-y)

Here the coordinates of the point D is (3,-3)

So, when its reflected over the x-axis to create the Point D'

D(3,-3) = D'(3,3)

Hence, if the point D is located at (3,-3) on the coordinate plane and the point D is reflected over the x-axis to create point D', then the ordered pair describes  the location of D' is (3,3)

Learn more about coordinate plane here

brainly.com/question/24134413

#SPJ1

6 0
1 year ago
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