Answer:
(e) the mean number of siblings for a large number of students has a distribution that is close to Normal.
Step-by-step explanation:
Central Limit Theorem
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean 
and standard deviation 
, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean and standard deviation 
.
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
By the Central Limit Theorem
The sampling distributions with a large number of students(at least 30) will be approximately normal, so the correct answer is given by option e.
Answer:
Step-by-step explanation:
1
- IQR's
- Ride A: 30 - 20 = 10
- Ride B: 30 - 10 = 20
- False, as 10 < 20
2
- Medians
- Ride A: 25
- Ride B: 20
- False, as 25 > 20
3
- Ranges
- Ride A: 45 - 5 = 40
- Ride B: 35 - 0 = 35
- TRUE, as 40 > 35
4
- Minimum
- Ride A: 5
- Ride B: 0
- TRUE, as 0 < 5
As consecutive odd numbers differ by two (example: 3, 5, 7), the first odd number can be expressed as 2n + 1, the next can be found by adding two to the first to get 2n + 1 + 2 which simplifies to 2n + 3. Finally the expression for the third consecutive odd integer can be found by adding two to the previous, 2n + 3, to get 2n + 5. Adding these three together and setting them equal to your sum gets the equation
2n + 1 + 2n + 3 + 2n + 5 = 63
Combine like terms and solve For n.
Once you have n, you must substitute it back into your three expressions (2n + 1, 2n + 3, 2n + 5) to find the three odd integers.
Hope this helps :)
Answer:
8 seconds
Step-by-step explanation:
400 divided by 50 is 8
