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crimeas [40]
3 years ago
12

Suppose that f(x) = x2 and g(x) = + 4/5x2. Which statement best compares the

Mathematics
1 answer:
Sauron [17]3 years ago
8 0

F(x)=x3 and g(7) = 982

<h3>kaoaksksjns</h3>
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Justin wants to buy a new bicycle, which costs $266.52. His parents have promised to contribute one-fourth of the cost of the bi
EleoNora [17]

Answer:

Step-by-step explanation:

7 0
3 years ago
24*43x22*8x67x890x10*3x6*1x8*1
lukranit [14]

Answer:

1032x176x67x890x30x6x8

1032×176×67×890×30×6×8x^6

1.56^13×x^6

4 0
3 years ago
If x=z+8 where z varies inversely as y and z=2 when y=3 find relation between y and x?​
sattari [20]

Answer:

y = 6/(x - 8).

Step-by-step explanation:

z = k/y    where k is a constant

2 = k/3

k = 6.

So z = 6/y

and  x = 6/y + 8

Multiply through by y:

xy = 6 + 8y

xy - 8y = 6

y(x - 8) = 6

y = 6/(x - 8)

5 0
3 years ago
A class at Middlebury school collected date on the types of movies students prefer. Complete each statement using the table.
likoan [24]

Based on the information of the table, you have:

1. The ratio is 105/150. By simplifying you get for the ratio 7/10.

2. The students that prefer action movies are 75+90 = 165 and the total numbe of students is 180+240 = 420. Then, the fraction of students who prefer action movies is:

165/420 = 11/28

3. The fraction of seventh graders students that prefer action movies is:

75/180 = 5/12

4. The percent of student that prefer comedy is:

105 + 150 = 255 total student that prefer comedy

420 total number of students

the fraction is:

(x/100)420 = 255

solve for x:

x = 255(100/420)

x = 60.71

the percent of students is 60.71%

5. The percent of eighth graders student who prefer action moveis is:

(x/100)240 = 90

x = 90(100/240)

x = 37.5

the percent of students is 37.5%

6. To determine which from the given grades has the greatest percent of student that prefer action movies, calculate the percent of student in seventh-grade:

(x/100)180 = 75

x = 75(100/180)

x = 41.66

the percent of student is 41.66%

then, seventh grade has the greatest percent of student that prefer action movies.

4 0
1 year ago
Find the missing side lengths. Leave your answers as radicals in simplest form.
Citrus2011 [14]

This is the isosceles right triangle, the diagonal of a square, the thing that so upset the Pythagoreans. The two sides and diagonal of a square are in ratio 1:1:\sqrt{2} so we get


u = v =  8


We could have also gotten this using Trig:


u = (8 \sqrt{2}) \sin 45^\circ = 8 \sqrt{2}/\sqrt{2} = 8


v = (8\sqrt{2})\cos 45^\circ = 8


Or by recognizing u=v because remaining angle is 45 so this must be isosceles so


u^2 + u^2 = (8 \sqrt{2})^2


2u^2 = 2 (8^2)


u = 8

8 0
4 years ago
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