2(n+3)
two times the sum of a number (n) and 3
Answer:
1/4
Step-by-step explanation:
3/12
Simplify. Both numbers can be divided by 3.
3/12 = 1/4
You can add them like this:
so if 156 + 213 + 109 was the equation then you would
first put them in order from biggest to smallest
213
156
+109
-----------
then add:
¹ ← ←
213 ↑
156 ↑
+109 ↑
---------↑ ( carry the 10 )
478 (add the ¹ )
then you get the answer 478!
hope that helps :)
Answer:
There is NO solution
Step-by-step explanation:
Considering 'y' be the number
Considering x be the smaller number
As 'y' is equal to twice a smaller number plus 3.
so

also
y is equal to twice the sum of the smaller number and 1.
so

so the system of equations become


solving







Therefore, there is NO solution.