The x-intercept of a graph is the point where the graph crosses the x-axis
<h3>(a) Graph</h3>
The function is given as:

See attachment for the graph of the function.
From the attachment, the approximated x-intercepts are -7 and -1
<h3>(b) Type of solution</h3>
From the attached graph, we can see that the curve crosses the x-axis at non-terminating decimals
Hence, the solutions of the equation are irrational.
<h3>(c) The vertex</h3>
This is the minimum or the maximum point of a parabola.
From the attached graph, the minimum point is at (-4,-7)
Hence, the coordinates of the vertex of the parabola is (-4,-7), and it is exact (not approximated)
Read more about parabolas at:
brainly.com/question/4061870
An explanatory variable is a type of independent variable. A response variable is a type of dependent variable. An explanatory variable is used to predict or explain differences in the response variable.
The first coordinate corresponds to independent variable and the second coordinate corresponds to dependent variable.
Since independent variable takes value 5 and dependent variable takes value 15, then the point (5,15) would be the point when plotted on a scatterplot.
Answer: correct choice D
Let's model the problem like a circle.
The circumference of a circle is given by:

Where,
r: radius of the circle.
Clearing the radius we have:

Then, replacing values we have:


Answer:
The best approximation for the radius of the tin is:

Hi, Sthefy! This is just a little bit of adding, not too hard! Okay, 5 tens. What is 1 ten equal to? 10!
2 tens? 20!
3 tens? 30!
You get the idea? Okay, so now we know that 5 tens are 50. Now, ones. All we need to do now is add 13 + 50! Let's break it down, make it easier.
13.. Hm, what can we do to make this easier?
Ah! Take away the 3 from 13 for now. So just 10 + 50. That's 60. Now, add the 3. 63! That wasn't hard, was it? I hope I helped you!
A contraction would make the image smaller.
A negative number reflects the image and changes the size based on the number.
To make an image smaller the factor needs to be less than 1
so -0.5 and 0.5 would make the image smaller since 0.5 is less than 1.