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NNADVOKAT [17]
3 years ago
15

Write the number equal to 5 tens and 13 ones.

Mathematics
1 answer:
tekilochka [14]3 years ago
3 0
Hi, Sthefy! This is just a little bit of adding, not too hard! Okay, 5 tens. What is 1 ten equal to? 10!
 
2 tens? 20!

3 tens? 30!
 
You get the idea? Okay, so now we know that 5 tens are 50. Now, ones. All we need to do now is add 13 + 50! Let's break it down, make it easier.

13.. Hm, what can we do to make this easier? 

Ah! Take away the 3 from 13 for now. So just 10 + 50. That's 60. Now, add the 3. 63! That wasn't hard, was it? I hope I helped you!
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Papessa [141]
The answer is 522 over 1111
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4 years ago
The augmented matrix of a system of equations has been transformed to an equivalent matrix in​ row-echelon form. Using​ x, y
jenyasd209 [6]

Answer: The system of equations is:

x + 2y + 2 = 4

y - 3z = 9

z = - 2

The solution is: x = -22; y = 15; z = -2;

Step-by-step explanation: ONe way of solving a system of equations is using the Gauss-Jordan Elimination.

The method consists in transforming the system into an augmented matrix, which is writing the system in form of a matrix and then into a <u>Row</u> <u>Echelon</u> <u>Form,</u> which satisfies the following conditions:

  • There is a row of all zeros at the bottom of the matrix;
  • The first non-zero element of any row is 1, which called leading role;
  • The leading row of the first row is to the right of the leading role of the previous row;

For this question, the matrix is a Row Echelon Form and is written as:

\left[\begin{array}{ccc}1&2&2\\0&1&3\\0&0&1\end{array}\right]\left[\begin{array}{ccc}4\\9\\-2\end{array}\right]

or in system form:

x + 2y + 2z = 4

       y + 3z = 9

               z = -2

Now, to determine the variables:

z = -2

y + 3(-2) = 9

y = 15

x + 30 - 4 = 4

x = - 22

The solution is (-22,15,-2).

4 0
3 years ago
(-7) x (-7)to the 11th power
masha68 [24]

Answer:

(-7)×(-7)=+49

You change the signs and multiple

5 0
3 years ago
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Find two complex numbers that have a sum of i10 a different of -4and a product of -29​
lianna [129]
<h2>-2+5i and 2+5i</h2>

Step-by-step explanation:

   Let the complex numbers be a+ib\textrm{ and }c+id.

Given, sum is 10i, difference is -4 and product is -29.

(a+c)+i(b+d)=10i ⇒ a+c=0,b+d=10

(a-c)+i(b-d)=-4 ⇒ a-c=-4,b-d=0

a=-2,c=2,b=5,d=5

(a+ib)(c+id)=(-2+5i)(2+5i)=-4-25=-29

Hence, all three equations are consistent yielding the complex numbers -2+5i\textrm{ and }2+5i.

8 0
3 years ago
What is the answer to this calculus problem???<br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bd%7D%7Bdx%7D%20%28e%20%7B%7D%5E
Len [333]

Answer:

see explanation

Step-by-step explanation:

Differentiate using the product rule

Given y = f(x)g(x), then

\frac{dy}{dx} = f(x). g'(x) + g(x). f'(x)

here f(x) = e^{x} ⇒ f'(x) = e^{x}

g(x) = cosx ⇒ g'(x) = - sinx

Hence

\frac{dy}{dx} = e^{x}(- sinx) + cosx e^{x}

                                   = e^{x}cosx - e^{x}sinx

3 0
3 years ago
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