The options Patel has to solve the quadratic equation 8x² + 16x + 3 = 0 is x = –1 Plus or minus StartRoot StartFraction 5 Over 8 EndFraction EndRoot.
<h3>Quadratic equation</h3>
8x² + 16x + 3 = 0
8x² + 16x = -3
8(x² + 2x) = -3
- Using completing the square
8(x² + 2x + 1) = -3 + 8
8(x² + 1) = 5
(x² + 1) = 5/8
- Taking the square root of both sides
(x + 1) = ± √5/8
x = -1 ± √5/8
Therefore,
x = –1 Plus or minus StartRoot StartFraction 5 Over 8 EndFraction EndRoot
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Answer:
Step-by-step explanation:
<em>Original question is attached</em>
<h3>Option 1</h3>
- C(x) = 25x + 50
- C(8) = 25*8 + 50 = $250
<h3>Option 2</h3>
- As per table, the rate of change is $30 per 2 hours.
- So 8 hours will cost
- $190 + $30 = $220
As we see the second option is cheaper so we should hire the Master Remodeling
Answer:
11+ 200% = 33 pounds
The percent increase is 200%
Step-by-step explanation:
Given:
A triangle ABC.
The given expression for b is:
To find:
The expression that is equivalent to b.
Solution:
According to the Law of Cosines,
It can be written as:
...(i)
We have,
...(ii)
On comparing (i) and (ii), we get
Therefore, the required values are 
.
Area of a square : One side x 2
Area of triangle : Width x Height then divide by 2
Area of <span>parallelogram : Width x Height
Area of Trapizoid : base 1 x base 2 then divide by 2, next multiply times the height
I'm pretty sure that all you need to know since this is an elementry school question.
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