Answer: 10 and 11
Step-by-step explanation: The best way to think about it is to think of the squares of numbers that equal close to 104. 10 squared is 100, and 11 squared is 121. Since 104 is between these two, we can assume that the square root of 104 must be in between their square roots, 10 and 11.
Wouldn’t it be called rounding
Answer:
The numbers would be 89,414 , 89,416, and 89,418
Step-by-step explanation:
In order to find this, start by setting the lowest number as x. Then we can determine that the next two even integers are x + 2 and x + 4. From this we can write the following equation.
2(x) + x + 2 = 268,244
3x + 2 = 268,244
3x = 268,242
x = 89,414
Since the first number is 89,414, we know the next two are 89,416 and 89,418.
Step-by-step explanation:
x= -2,
(x - 5) / 2= -6
( (-2) - 5) / 2= -6
(-7) / 2 = -6
-3.5 = - 6
right hand side not equal to left hand side of this equation.so,x= -2 cannot exist for this equation.
x=2,
(x - 5) / 2= -6
(2 - 5) / 2= -6
(-3) / 2= -6
-1.5 = - 6
right hand side not equal to left hand side of this equation.so,x= 2 cannot exist for this equation.
x= -17
(x - 5) / 2= -6
( ( -17) - 5) / 2= -6
(- 22) / 2= -6
-11 = -6
right hand side not equal to left hand side of this equation.so,x= -17 cannot exist for this equation.
x= -7,
(x - 5) / 2= -6
( ( -7) -5) / 2= -6
(-12) / 2= -6
-6= -6
right hand side equal to left hand side of this equation.so,x= -7 exist for this equation.
Answer:
see below
Step-by-step explanation:
3t+1> 3t + 2
Subtract 3t from each side
1>2
This is never true so there is no solution
Since the variable terms are the same, we only have to look at the constants
